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Phoenix [80]
3 years ago
9

You are In-line skates at the top of a small hill. Your potential energy is equal to 1000 J. The last time we checked, your mass

was 60 KG. What is the height of the hill?
Physics
1 answer:
stira [4]3 years ago
3 0

A) <u>Weight = mass × acceleration (due to gravity)  </u>

= 60×9.8  

= 588 N  

<u>B) Potential energy = mass x gravity x change in height </u>

1,000 = 60.0 x 9.8 x h

h =  1.7 m      

<u>C) Kinetic energyF = potential energyI </u>

KEF = 1/2mv2  

PEI = mgh = 1,000 J

1/2mv2 = 1,000

1/2(60.0)v2 = 1,000  

v2 = 33.33

v = 5.77 m/s

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Space vehicles traveling through Earth's radiation belts can intercept a significant number of electrons. The resulting charge b
Elena L [17]

Answer:

a) 0.167 μC/m^2

b) 1.887 * 10^4 V/m

Explanation:

Hello!

First let's find the surface charge density:

a)

Since thesatellite is metallic, the accumalted charge will be uniformly distribuited on its surface. Therefore the charge density σ will be:

σ = Q/A

Where A is the area of the satellite, which is:

A=4πr^2 = πd^2 = π(1.9m)^2

Therefore:

σ = (1.9)/(π (1.9)^2) μC/m^2 = 0.167 μC/m^2

Now let's calculate the electric field

b)

Just outside the surface of the satellite the elctric field will be:

E = σ/ε0

Where      ε0=8.85×10^−12 C/Vm

Therefore:

E = (0.167*10^-6 C/m^2) / (8.85*10^-12  C/Vm) = 0.01887 *10^6 V/m

E = 1.887 * 10^4 V/m

5 0
2 years ago
NEES HELP!!!!
OLga [1]

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

6 0
2 years ago
Question 2 of 5 Instructions:Select the correct answer. What do scientists use to determine the temperature of a star? thermomet
Lena [83]
Scientists use the color of a star to determine its temperature.
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4 0
3 years ago
Read 2 more answers
A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler
Pepsi [2]

Answer:

331665750000\ m/s^2

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = 1.989\times 10^{30}\ kg

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2

The gravitational acceleration at the surface of such a star is 331665750000\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s

The velocity of the object would be 3257806.62409 m/s

8 0
3 years ago
How much energy (in kWh) can you get from a 72 cell solar panel in one year?
Mumz [18]
Answer:72,000
Explanation:
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