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Phoenix [80]
3 years ago
9

You are In-line skates at the top of a small hill. Your potential energy is equal to 1000 J. The last time we checked, your mass

was 60 KG. What is the height of the hill?
Physics
1 answer:
stira [4]3 years ago
3 0

A) <u>Weight = mass × acceleration (due to gravity)  </u>

= 60×9.8  

= 588 N  

<u>B) Potential energy = mass x gravity x change in height </u>

1,000 = 60.0 x 9.8 x h

h =  1.7 m      

<u>C) Kinetic energyF = potential energyI </u>

KEF = 1/2mv2  

PEI = mgh = 1,000 J

1/2mv2 = 1,000

1/2(60.0)v2 = 1,000  

v2 = 33.33

v = 5.77 m/s

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A ship leaves a port at noon and travels due west at 20 knots. At 6 PM, a second ship leaves the same port and travels northwest
Amanda [17]

Answer:

v = 12.44 Knots

Explanation:

First ship starts at Noon with speed 20 Knots towards West

now we know that 2nd ship starts at 6 PM with speed 15 Knots towards North West

so after time "t" of 2nd ship motion the two ships positions are given as

r_1 = 20(t + 6)\hat i

r_2 = 15(t)(cos45\hat i + sin45\hat j)

now we can find the distance between two ships as

x = \sqrt{(20(t + 6) - 10.6 t)^2 + (10.6t)^2}

now we have

x^2 = (120 + 9.4 t)^2 + (10.6 t)^2

x^2 = 200.72 t^2 + 14400 + 2256 t

now we will differentiate it with respect to time

2x\frac{dx}{dt} = 401.44 t + 2256

here we know that

t = \frac{90}{15} = 6 hours

so we have

x = 187.5

now we have

2(187.5) v = 401.44(6) + 2256

v = 12.44 Knots

5 0
3 years ago
Work done= ________ transferred
mamaluj [8]

Answer:

Work done= Energy transferred

Explanation:

Work is the transfer of energy. In physics we say that work is done on an object when you transfer energy to that object. If you put energy into an object, then you do work on that object (mass).

4 0
3 years ago
A runner of mass 51.8 kg starts from rest and accelerates with a constant acceleration of 1.31 m/s^2 until she reaches a velocit
Stells [14]

Answer:32.24 s

Explanation:

Given

mass of runner (m)=51.8 kg

Constant acceleration(a)=1.31 m/s^2

Final velocity (v)=5.47 m/s

Time taken taken to reach 5.47 m/s

v=u+at

5.47=0+1.31\times t

t=\frac{5.47}{1.31}=4.17 s

Distance traveled during this time is

s=ut+\frac{1}{2}at^2

s=\frac{1}{2}\times 1.31\times 4.17^2=11.42 m

So remaining distance left to travel with constant velocity=153.57 m

thus time =\frac{distance}{speed}

t_2=\frac{153.57}{5.47}=28.07 s

Total time=28.07+4.17=32.24 s

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3 years ago
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<span>The screw is really just an inclined plane covered around with a tiny pole. The wedge is definitely an inclined plane, since it starts with a point, then rises getting thicker, as an inclined plane. </span>
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