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3 years ago

Radius is dash of the diameter

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

Radius is 1/2 of the diameter

Diameter is 2 of the radius

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What is the slope of the line that passes through the points (1, 2) and (3, 12)?

Molodets [167]

Answer:

Slope is 5

Step-by-step explanation:

(1, 2) and (3, 12)

m= (y2-y1)/(x2-x1)

m= (12-2)/(3-1)

m= 10/2

m= 5

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3 years ago

A bowl contains blueberries and strawberries. There are a total of 10 berries in the bowl. The ratio of blueberries to strawberr

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Answer:

4 strawberries and 6 blueberries

Step-by-step explanation:

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3 years ago

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Billy watched the clown car drive up to the circus and saw

nekit [7.7K]

14%=56%
56%=56/100=0.56

14=0.56 of all
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4 years ago

7 copies 0f 1 fourth what does it equal

kvasek [131]

7 copies I assume means multiplication. 7 x 1/4=7/4. When multiplying fractions, the numerator is multiplied.

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3 years ago

Find the equation of the line tangent to the graph of

garik1379 [7]

Answer:

$\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}$

Step-by-step explanation:

We want to find the equation of the line tangent to the graph of:

$\displaystyle y=\sin^{-1}\big(\frac{x}{5}\big)\text{ at } x=\frac{5}{2}$

So, we will find the derivative of our equation first. Applying the chain rule, we acquire that:

$\displaystyle y^\prime=\frac{1}{\sqrt{1-(\frac{x}{5})^2}}\cdot\frac{1}{5}$

Simplify:

$\displaystyle y^\prime=\frac{1}{5\sqrt{1-\frac{x^2}{25}}}$

We can factor out the denominator within the square root:

$\displaystyle y^\prime =\frac{1}{5\sqrt{\frac{1}{25}\big(25-x^2)}}$

Simplify:

$\displaystyle y^\prime=\frac{1}{\sqrt{25-x^2}}$

So, we can find the slope of the tangent line at x = 5/2. By substitution:

$\displaystyle y^\prime=\frac{1}{\sqrt{25-(5/2)^2}}$

Evaluate:

$\displaystyle y^\prime=\frac{1}{\sqrt{75/4}}=\frac{1}{\frac{5\sqrt{3}}{2}}=\frac{2\sqrt{3}}{15}$

We will also need the point at x = 5/2. Using our original equation, we acquire that:

$\displaystyle y=\sin^{-1}(\frac{1}{2})=\frac{\pi}{6}$

So, a point is (5/2, π/6).

Finally, by using the point-slope form, we can write:

$\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}(x-\frac{5}{2})$

Distribute:

$\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}x+\frac{-\sqrt{3}}{3}$

Isolate. Hence, our equation is:

$\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}$

7 0

3 years ago

Radius is dash of the diameter ​

Radius is dash of the diameter