Answer : One mole of an ideal gas occupies a volume of 22.4 liters at STP.
Explanation :
As we know that 1 mole of substance occupies 22.4 liter volume of gas at STP conditions.
STP stands for standard temperature and pressure condition.
At STP, pressure is 1 atm and temperature is 273 K.
By using STP conditions, we get the volume of 22.47 liter.
Hnece, the one mole of an ideal gas occupies a volume of 22.4 liters at STP.
The urinary system filters and gets rid of waste from the body.
Answer:
23.8
Explanation:
Formula
weight % = weight of solute/ weight of solution x 100
weight of solution = weight of salt + weight of water
weight of solution = 1.62 lb + 5.20 lb = 6.82 lb
weight % = 1.62 / 6,82 x 100
weight % = 0.238 x 100
weight % = 23.8
Answer:
B
Explanation:
The normal way to express an energy reaction is to put the energy on the left. Then you can make a rule.
- If the energy on the left is plus then the reactants require energy. The reaction is endothermic -- energy is taken from the environment.
- If the energy is minus when it is on the left. then the reactants give up energy. The reaction is exothermic and energy is given to the environment.
2CO(g)+O2(g) - energy --> 2CO2(g)
Exothermic
Answer:
V₂ = 285 mL
Explanation:
Given data:
Initial volume of bag = 250 mL
Initial temperature = 19.0°C
Final temperature = 60.0°C
Final volume = ?
Solution:
The given problem will be solved by using Charles Law,
This law stated that " The volume of given amount of gas at constant pressure and constant number of moles is directly proportional to its temperature"
Mathematical relationship:
V₁/T₁ = V₂/T₂
Now we will convert the temperature into kelvin.
Initial temperature = 19.0 + 273 = 292K
Final temperature = 60.0 + 273 = 333K
Now we will put the values in formula:
V₁/T₁ = V₂/T₂
250 mL / 292K = V₂/ 333K
0.856 mL /K = V₂/ 333K
V₂ = 0.86×333K. mL /K
V₂ = 285 mL
