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IrinaVladis [17]
3 years ago
5

3. The density of acetic anhydride is 1.08 g/mL. How many moles of acetic anhydride are used in this experiment

Chemistry
1 answer:
Burka [1]3 years ago
4 0

Answer:

Number of moles = 0.1058 mol

Explanation:

Density = 1.08 g/mL

Volume = 10ml

Density = Mass / Volume

Mass = Density * Volume

Mass = 1.08 * 10 = 10.8g

The molar mass of acetic anhydride = 102.09 g/mol

Molar mass = Mass / Moles

Upon solving for moles;

Moles = Mass / Molar mass

Moles = 10.8 / 102.09 = 0.1058 mol

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What are the rectants of photosynthesis ?
BabaBlast [244]

Answer:

Light energy, water and carbon dioxide

Explanation:

First, let’s look at the photosynthesis equation:

light energy + water + carbon dioxide —> glucose + oxygen

The reactants are what go in and are used to create the products.

In photosynthesis, light energy from the sun, water and carbon dioxide are used to make glucose and oxygen.

Therefore, the reactants are light energy, water, and carbon dioxide.

6 0
3 years ago
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State the definition of the partial molar Gibbs energy.
balu736 [363]

Explanation :

As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.

G=G(T,P,n_1,n_2)

where,

n_1\text{ and }n_2 is the amount of component 1 and 2 in the system.

Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable (T,P,n_j) are kept constant are known as partial molar Gibbs free energy of i^{th} component.

For a substance in a mixture, the chemical potential (\mu) is defined as the partial molar Gibbs free energy.

The expression will be:

\bar{G_i}=\mu_i=\frac{\partial G}{\partial n_i}_{(T,P,n_j)}

where,

T = temperature

P = pressure

n_i\text{ and }n_j is the amount of component 'i' and 'j' in the system.

4 0
3 years ago
What is the percent magnesium in a sample made of 24g Mg and 70gCl?
seropon [69]

Answer:

Total percent of magnesium in sample = 25.5%

Explanation:

Given:

Mass of magnesium = 24 gram

Mass of chlorine = 70 gram

Find:

Total percent of magnesium in sample = ?

Computation:

Total mass of sample = Mass of magnesium + Mass of chlorine

Total mass of sample = 24 gram + 70 gram

Total mass of sample = 94 gram

Total percent of magnesium in sample = [Mass of magnesium / Total mass of sample]100

Total percent of magnesium in sample = [24/94]100

Total percent of magnesium in sample = [0.255]100

Total percent of magnesium in sample = 25.5%

5 0
3 years ago
Help me please!!
WINSTONCH [101]

Answer:

663 g

Explanation:

Step 1: Write the balanced equation

2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃

Step 2: Calculate the moles corresponding to 825 L of CO₂

At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.

825 L × 1 mol/22.4 L = 36.8 mol

Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂

The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.

Step 4: Calculate the mass corresponding to 36.8 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

36.8 mol × 18.02 g/mol = 663 g

3 0
2 years ago
The reaction below is at equilibrium at a temperature T. There are four possible changes listed. Select all the changes that wil
katovenus [111]

Answer:

The correct answer is B.

Explanation:

Heterogeneous equilibrium is that in which reagents and products are present in more than one phase.

When the reaction is carried out in a closed container, three equilibrium phases are present: solid magnesium oxide, solid magnesium sulfate and gaseous sulfur trioxide.

Hence, the equilibrium contant is given by:

K=\frac{[MgSO_4]}{[MgO][SO_3]} =\frac{1}{[SO_3]}

The concentrations in the equilibrium equation are the relationships of the real concentrations between the concentrations in the standard state. Since the standard state of a pure solid is the pure solid itself, the ratio of concentrations for a pure solid is equal to one.

Now, we analyse each statement:

I) As the reaction is endothermic (ΔH>0), increasing the temperature shifts the balance to the right because excess heat will be used to form more products.

II) Increasing the volume will decrease the concentration of SO₃, so Q>K and then this shifts the balance to the left.

III) As it is a heterogeneous balance, adding MgO will not affect the balance.

IV) Removing SO3 will decrease its concentration and therefore the reaction equilibrium will shift to the left.

6 0
2 years ago
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