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dlinn [17]
3 years ago
6

List out the effects seen inplants due to lack of phosphorus.​

Chemistry
1 answer:
valkas [14]3 years ago
4 0

Answer:

Plants normally turn dark green and look stunted (both leaves and stalks). Older leaves are first affected and may become violet. Sometimes the brown tips of the leaves remain fragile and their maturity seems to be delayed.

Explanation:

it is what it is booiiii

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Vanyuwa [196]
16 I think but I could be wrong lol
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3 years ago
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How many moles of oxygen must be placed
Annette [7]

0.24 moles of oxygen must be placed  in a 3.00 L container to exert a pressure of 2.00 atm at 25.0°C.

The variables given are Pressure, volume  and temperature.

Explanation:

Given:

P = 2 atm

V = 3 litres

T = 25 degrees or 298.15 K by using the formula 25 + 273.17 = K

R  = 0.082057 L atm/ mole K

n (number of moles) = ?

The equation used is of Ideal Gas law:

PV = nRT

n = \frac{PV}{RT}

Putting the values given for oxygen gas in the Ideal gas equation, we get

n = \frac{2 x 3}{0.082157 x 298.15}

  = 0.24

Thus, from the calculation using Ideal Gas law it is found that 0.24 moles of oxygen must be placed in a container.

Ideal gas law equation is used as it tells the relation between temperature, pressure and volume of the gas.

3 0
3 years ago
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A piece of fossilized wood has a carbon-14 radioactivity that is 1/4 that of new wood. the half-life of carbon-14 is 5730 years.
Marizza181 [45]

Answer:

1.146 x 10⁴ year.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

<em></em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = ??? years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]

(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.

∴ <em>t </em>= 1.386/ (1.21 x 10⁻⁴ year⁻¹) =  <em>1.146 x 10⁴ year.</em>

3 0
4 years ago
What is the volume of a 6.2 M potassium chloride solution that contains 18.25 mols of solute? Show your work, please
slega [8]

Answer:

The answer to your question is Volume = 2.94 L

Explanation:

Data

Concentration = 6.2 M

Number of moles = 18.25

Volume = ?

Process

1.- Use the Molarity formula to solve this problem

      Molarity = Number of moles / Volume

- Solve for volume

       Volume = Number of moles / Molarity

2.- Substitution

       Volume = 18.25 / 6.2

3.- Simplification

       Volume = 2.94 L

3 0
3 years ago
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D
Feliz [49]

Answer:

Be, Mg, Ca, Sr are in the same group

Explanation:

these elements are in alkaline earth metals

mark in as a brainly plz

7 0
3 years ago
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