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dlinn [17]
3 years ago
6

List out the effects seen inplants due to lack of phosphorus.​

Chemistry
1 answer:
valkas [14]3 years ago
4 0

Answer:

Plants normally turn dark green and look stunted (both leaves and stalks). Older leaves are first affected and may become violet. Sometimes the brown tips of the leaves remain fragile and their maturity seems to be delayed.

Explanation:

it is what it is booiiii

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Write the empirical formula
stira [4]

Answer:

1)  NH_{4}IO_{3}\\2) Pb(IO_{3})_{4} \\3)  NH_{4}(C_{2}H_{3}O_{2})\\4) Pb(C_{2}H_{3}O_{2})_{4}

Explanation:

1) NH_{4}^{+}IO_{3}^{-} ---> NH_{4}IO_{3}\\2) Pb^{4+}(IO_{3}^{-})_{4} --->Pb(IO_{3})_{4} \\3) NH_{4}^{+}(C_{2}H_{3}O_{2})^{-} ---> NH_{4}(C_{2}H_{3}O_{2})\\4) Pb^{4+}(C_{2}H_{3}O_{2})^{-} _{4} --->Pb(C_{2}H_{3}O_{2})_{4}

7 0
3 years ago
Чому вирівнювання хімічних рівнянь є обов´язковим
Sav [38]

what is your question?

plz ask in English language

3 0
3 years ago
How many grams of mercury are needed to react completely with 157g of sulfur to form hgs?
Salsk061 [2.6K]
<span>To solve this we need to balance the equations first.
 So Hg + S --> HgS is balanced
 One mole of Hg requires one mole of S to form one mole of HgS.
 Number of moles of Sulphur = mass/ molar mass = 157/32 = 4.906
So 4.90 moles of S reacts with 4.90 moles of Hg.
Hence there are 4.90 moles of 4.90 of Hg.
 Mass = number of moles * molar mass of Hg
Mass = 4.906 * 200.59 = 982.891g</span>
8 0
3 years ago
Read 2 more answers
A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled th
erica [24]

Answer:

Explanation:

  Ions which will  be definitely  absent -

Ag⁺ , Hg₂⁺ , Pb⁺², because their chlorides are insoluble in water.

Ba⁺² ,Ca⁺² because their carbonates are insoluble in water,

Ions which will be definitely present  

Cu⁺² , Pb⁺² . Hg⁺² , Sb⁺³ , Sn⁺² , because their sulphides are insoluble at pH = 8.

For the rest nothing can be said.

 

5 0
3 years ago
The table shows the students data from an investigation about a plant growth and five plants of the same type what is the best w
NARA [144]

Answer:

This question is incomplete

Explanation:

The question is incomplete because of the absence of the table but since the question says there are data from an investigation about a plant growth and five other plants (making six) of the same type, the best way to display this type of data for analyst is to use the grouped bar chart. <u>The grouped bar chart will display the data obtained (from an investigation on plant growth) from different students on each of the six plants (of the the same type)</u>.

Colours are usually used to identify the bars (of a group) or could be used to separate the group from other groups but in this case, colours are better used to identify the bars of a group.

8 0
4 years ago
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