Answer:
The required volume is 0.84 L
Explanation:
Given,
Mass of O2 gas = 1.20 g
We know,
At STP, molar volume of all gases is 22.4 L
and Molar mass of O2 gas is 32 g
Now,
Number of moles = mass/molar mass
= 1.20/32
= 0.0375
Again,
At STP,
Number of moles = Volume/Molar volume
or, Volume = Number of moles X Molar Volume
or Volume = 0.0375 X 22.4
∴ Volume = 0.84 L
So, the required volume is 0.84 L
<span>2<span>C6</span><span>H6</span>O(l)+17<span>O2</span>−−>12C<span>O2</span>(g)+12<span>H2</span>O(l)</span>
<span>2S<span>O2</span>(g)+<span>O2</span>(g)−−>2S<span>O3</span>(g)</span>
<span><span>N2</span>(g)+<span>O2</span>(g)−−>2NO(g)</span>
<span>2Na(s)+B<span>r2</span>(l)−−>2NaBr(s)</span><span>
On the 1st 3 I have
12 -17 = -5
2 - 3 = -1
2 - 2 = 0
For the last one:
</span><span>Delta n=0</span><span>
</span>
Try G I think I’m correct
Answer : The temperature of this gas will be, 206.9 K
Explanation :
The expression for the kinetic energy per molecule of monoatomic gas (argon) is:
...........(1)
The expression for the kinetic energy per molecule of diatomic gas (nitrogen gas) is:
.............(2)
The total kinetic energy of the molecule will be,
Now put all the expression in this, we get:
Now put all the given values in this expression, we get:
Therefore, the temperature of this gas will be, 206.9 K
