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3 years ago

For work to be done on the object the object has to

Physics

2 answers:

Fittoniya [83]3 years ago

6 0

Answer:

Work is defined by the movement done by an object caused by a force.

So for work to be done on an object, the object must be receiving a force and being moved or changing position, and we can synthesize this by "the object has to accelerate"

Where acceleration implies a force applied, and an accelerating body is changing his velocity, so it is moving.

Nata [24]3 years ago

3 0

Gain energy

good luck!

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Can someone please help me on thisss

Ivahew [28]

Answer 2 i did this before

4 0

3 years ago

You walk 100m due north. You then turn and walk 55m due east. You then make another turn and walk 12m due south. What is the res

lord [1]

Answer:

Explanation:

Important here is to know that due north is a 90 degree angle, due east is a 0 degree angle, and due south is a 270 degree angle. Then we find the x and y components of each part of this journey using the sin and cos of the angles multiplied by each magnitude:

$A_x=100cos90\\A_x=0\\B_x=55cos0\\B_x=55\\C_x=12cos270\\C_x=55$

Add them all together to get the x component of the resultant vector, V:

$V_x=55$

Do the same to find the y components of the part of this journey:

$A_y=100sin90\\A_y=100\\B_y=55sin0\\B_y=0\\C_y=12sin270\\C_y=-12$

Add them together to get the y component of the resultant vector, V:

$V_y=88$

One thing of import to note is that both of these components are positive, so the resultant angle lies in QI.

We find the final magnitude:

$V_{mag}=\sqrt{55^2+88^2}$ and, rounding to 2 sig dig's as needed:

$V_{mag}=$ 1.0 × 10² m; now for the direction:

$\theta=tan^{-1}(\frac{88}{55})=$ 58°

7 0

3 years ago

Which of the following is the proper unit for measuring power? Newton Joules Watts Meters

fredd [130]

The unit for power is Watts. the newton is a unit for force. joules for energy and meters for distance

3 0

3 years ago

What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)

puteri [66]

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

3 0

3 years ago

In the figure below the pulley is a solid disk of mass M and radius R with rotational inertia MR 2/2. Two blocks one of mass m a

matrenka [14]

Assuming you are looking for the acceleration a:

1. $m_1a = T_1 -m_1g$
2. $m_2a = m_2g - T_2$
where T is the tension and a is the acceleration of the blocks. The acceleration of the two blocks and the acceleration of the pulley must be equal.

The torque on the pulley is given by:
3. $\tau = \overrightarrow r \times \overrightarrow F = (T_2 - T_1)R = I\alpha = \frac{1}{2} MR^2 \frac{a}{R}$
where $I = \frac{1}{2} mR^2$ and $a = \alpha R$ .

Combining the three equations:
$T_2 - T_1 = \frac{1}{2} Ma \\ m_2g - m_2a -m_1g - m_1a = (m_2-m_1)g - (m_1 + m_2)a = \frac{1}2}Ma \\ \\ a = \frac{(m_2 - m_1)g}{m_1 + m_2 + \frac{1}{2}M }$

6 0

3 years ago