Answer:
A) I = Io 0.578, B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter
Explanation:
A) Light passing through a polarizer must comply with the / bad law
I = Io cos2 tea
Where is at the angle of the polarizer and incident light
I = Io cos2 45
I = Io 0.578
Therefore the beam intensity is 0.578 of the incident intensity
.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter
Answer:
1.3.
Explanation:
From the question given above, the following data were obtained:
Sine of incident angle (Sine i) = 0.217
Sine of refracted angle (Sine r) = 0.173
Refractive index (n) =?
From snell's law, the Refractive index is simply defined as the ratio of the sine of the incident angle to sine of the refracted angle. Mathematically, it is expressed as:
Refractive index = Sine of incident angle / sine of refracted angle
n = Sine i / Sine r
With the above formula, we can obtain index of refraction as shown below:
Sine of incident angle (Sine i) = 0.217
Sine of refracted angle (Sine r) = 0.173
Refractive index (n) =?
n = Sine i / Sine r
n = 0.217 / 0.173
n = 1.3
Thus, the index of refraction is 1.3.
Mass, m = 4g = 0.004 kg
Velocity, = 50cm/s = 0.5m/s
Distance, 10cm = 0.1m
The wall would have to resist the energy acquired by the bullet.
Kenetic Energy of bullet = Resistance offered by the wall.
1/2 mv² = Resistance Force * Distance
(1/2) * 0.04 * 0.5 * 0.5 = F * 0.1
0.5 * 0.04 * 0.5 * 0.5 = F * 0.1
0.5 * 0.04 * 0.5 * 0.5/0.1 = F
0.05 = F
Therefore, Resistance offered by the wall = 0.05 N
Answer:
False
Explanation:
When a driver is impaired the brain will need an extra second or two to wake up, after it does wake up it tends to drift off regularly.
Well this is question is easy. I mean i’m the one to say the least, The answer is.. SIKE L bozo imagine not knowing the answer
