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3 years ago

For work to be done on the object the object has to

Physics

2 answers:

Fittoniya [83]3 years ago

6 0

Answer:

Work is defined by the movement done by an object caused by a force.

So for work to be done on an object, the object must be receiving a force and being moved or changing position, and we can synthesize this by "the object has to accelerate"

Where acceleration implies a force applied, and an accelerating body is changing his velocity, so it is moving.

Nata [24]3 years ago

3 0

Gain energy

good luck!

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Explain integration and differentiation in simple method!

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Differentiation in its simplest of terms means breaking something into small parts. On the other hand, integration is taking those really small parts and gluing them in the right order. In short, these terms are the direct opposite or inverses of each other. The term which can tell you how fast you are going at a moment in time at ones current location is called a derivative. The term on the other hand, which can tell you how far you have travelled if you have been keeping track of your location and your time is what an integral is referred to. It is like differentiation only needs knowledge on the local neighbourhood while integration will need the knowledge on a global knowledge.

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True or false. there would be no like in earth without the sun

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3 years ago

Example 3 :

kherson [118]

The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.

<h3>How to determine the friction factor</h3>

Using the formula

μ = viscosity = 0. 06 Pas

d = diameter = 120mm = 0. 12m

V = velocity = 1m/s and 3m/s

ρ = density = 0.9

a. Velocity = 1m/s

friction factor = 0. 52 × $\frac{0. 06}{0. 12* 1* 0. 9}$

friction factor = 0. 52 × $\frac{0. 06}{0. 108}$

friction factor = 0. 52 × 0. 55

friction factor $= 0. 289$

b. When V = 3mls

Friction factor = 0. 52 × $\frac{0. 06}{0. 12 * 3* 0. 9}$

Friction factor = 0. 52 × $\frac{0. 06}{0. 324}$

Friction factor = 0. 52 × 0. 185

Friction factor $= 0.096$

Loss When V = 1m/s

Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter

Head loss = 0. 289 × $\frac{1}{2*6. 6743 * 10^-11}$ × $\frac{1^2}{0. 120}$ × $\frac{1}{100}$

Head loss = 1. 80 × 10^8

Head loss When V = 3m/s

Head loss = $0. 096$ × $\frac{1}{1. 334 *10^-10}$ × $\frac{3^2}{0. 120}$ × $\frac{1}{100}$

Head loss = 5. 3× 10^8

Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.

Learn more about friction here:

brainly.com/question/24338873

#SPJ1

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1 year ago

Antagonistic muscles move a body part in _____. 1. the same direction

alexdok [17]

Answer: Opposite direction

Skeletal muscles arise in antagonistic pairs where the muscles contract to produce opposite movements at the same joint. Antagonistic muscles move a body part in one direction by contraction, the other moves that part in opposite direction.

In addition, when a muscle contracts to produced movement, its antagonist relaxes to allow movement to take place such as biceps muscles is a flexor muscle for elbow joint and triceps is the antagonist.

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3 years ago

Read 2 more answers

The volume of a balloon an be approximated by V = 4 3 π r 3 V=43πr3. If air is leaking from the balloon at a rate of 56 cubic ce

11Alexandr11 [23.1K]

Answer:

The rate the radius of the balloon shrinking at the moment the radius is 5 centimeters is 0.1783 cm/s

Explanation:

Here we have

dV/dt = 56 cm³/s

$\frac{dV}{dt} = \frac{d}{dt}(\frac{4}{3}\pi r^3) = \frac{4}{3}\pi\cdot3r^2 \frac{dr}{dt}$