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3 years ago

For work to be done on the object the object has to

Physics

2 answers:

Fittoniya [83]3 years ago

6 0

Answer:

Work is defined by the movement done by an object caused by a force.

So for work to be done on an object, the object must be receiving a force and being moved or changing position, and we can synthesize this by "the object has to accelerate"

Where acceleration implies a force applied, and an accelerating body is changing his velocity, so it is moving.

Nata [24]3 years ago

3 0

Gain energy

good luck!

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Two equal forces are applied to a door. The first force is applied at the midpoint of the door; the second force is applied at t

Olenka [21]

Answer:

b) the second at the doorknob.

Explanation:

The torque applied by a force is given by the equation

$\tau = F_p d$

where

$\tau$ is the torque

$F_p$ is the component of the force perpendicular to the direction between the axis of rotation and the point of application of the force

d is the arm (the distance between the axis of rotation and the point of application of the force)

In this problem, we have two equal forces F both applied perpendicular to a door, so

$F_p = F$

The first force is applied at the midpoint of the door; if we call L the width of the door, then the arm of this force is $d_1=\frac{L}{2}$ , so the torque applied by this first force is

$\tau_1 = F\frac{L}{2}$

The 2nd force instead is applied at the doorknob, so the arm in this case is L:

d = L

So, the torque exerted by the second force is

$\tau_2 = FL$

Therefore, we see that the 2nd force exerts a greater torque.

5 0

2 years ago

C6H12O6 + 6O2 6CO2+6H2O + energy Which statement correctly compares the reactants and products of the equation?

ryzh [129]

The true statement about the equation of respiration is:

The mass of the reactants is the same as the mass of the products; option C.

<h3>What is respiration?</h3>

Respiration is the process by which living organisms break down large molecules such as glucose into smaller molecules such a carbon dioxide and water to release energy in the form of ATP.

Respiration are of two types in living organisms:

Aerobic respiration which requires oxygen
anaerobic respiration that does not require oxygen

The equation of aerobic respiration is given below:

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O + energy

In the given equation above, glucose reacts i the presence of oxygen is broken down into carbon dioxide and water and energy is released.

According to the law of conservation of mass, the mass of reactants is equal to the mass of the products.

Learn more about respiration at: brainly.com/question/22673336

#SPJ1

Note that the complete question is given below:

Respiration describes the process that living cells use to release energy by combining sugar and oxygen. The primary chemical changes that happen during respiration are shown in the equation below.

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O + energy

Which statement correctly compares the reactants and products of the equation?

The mass of the reactants is less than the mass of the products.

The mass of the reactants is greater than the mass of the products.

The mass of the reactants is the same as the mass of the products.

The number of reactant molecules is greater than the number of products.

5 0

1 year ago

In Hooke's law, what does k represent?

kicyunya [14]

For Plato, K represents the stiffness of the spring. Hope this helps!

3 0

3 years ago

Read 2 more answers

Using a rope that will snap if the tension in it exceeds 356 N, you need to lower a bundle of old roofing material weighing 478

klasskru [66]

Answer:

a) 2.5 m/s²

b) 6.12 m/s

Explanation:

Tension of rope = T = 356N

Weight of material = W = 478 N

Distance from the ground = s = 7.5 m

Acceleration due to gravity = g = 9.81 m/s²

Mass of material = m = 478/9.81 = 48.72

Final velocity before the bundle hits the ground = v

Initial velocity = u = 0

Acceleration experienced by the material when being lowered = a

a) W-T = ma

⇒478-356 = 48.72×a

$\Rightarrow \frac{122}{48.72} = a$

⇒a = 2.5 m/s²

∴ Acceleration achieved by the material is 2.5 m/s²

b) v²-u² = 2as

⇒v²-0 = 2×2.5×7.5

⇒v² = 37.5

⇒v = 6.12 m/s

∴ Velocity of the material before hitting the ground is 6.12 m/s

5 0

3 years ago

If a 2,000-kg car hits a tree with 500 n of force over a time of 0.5 seconds, what is the magnitude of its impulse?

Elden [556K]

Impulse = Force * time
Impulse = 500N *0.5 s =250 N*s

4 0

2 years ago

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