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ZanzabumX [31]
3 years ago
8

Many scientific discoveries are made by chance. While studying one phenomenon, a scientist may discover a different one. Such wa

s the case when William Herschel discovered the planet Uranus in 1781. Herschel was charting faint stars in the sky, when he discovered something that was not a star. How can astronomers tell the difference between a star and a planet
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

One simple explanation is that planets move, while stars remained fixed in the sky. You can observe a planet's orbit, but a star will stay in the same position.

Explanation:

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How many neutrons does element X if it’s atomic number is 28 and its mass number is 87
Sergeeva-Olga [200]

the answer is 59 neutrons


7 0
3 years ago
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those a
Nat2105 [25]

Answer:

Explanation:

Given

diameter d=20 \mu m

density \rho =1300 kg/m^3

frequency \nu =150 Hz

Length of silk strand L=14 cm

Velocity in the string is as follows

\nu =\sqrt{\frac{T}{\mu }}

The expression for Fundamental Frequency

f=\frac{\nu }{2l}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\mu }}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\frac{m}{l}}}

f=\frac{1}{2l}\times \sqrt{\frac{Tl}{\rho V}}

Squaring

f^2=\frac{1}{4l^2}\times \frac{Tl}{\rho V}

T=4\rho \cdot A\cdot l^2\cdot f^2

T=4\times 1300\times \frac{\pi }{4}(20\times 10^{-6})^2\times (0.14)^2\times 150^2

T=7.2\times 10^{-4} N

8 0
4 years ago
So my grades have come up a little but also went down a lot This app has really helped me!!
ddd [48]

Answer:

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6 0
3 years ago
Read 2 more answers
3. Liquid nitrogen at 90 K, 400 kPa flows into a probe used in a cryogenic survey. In the return line the nitrogen is then at 16
devlian [24]

Answer:

Specific heat transfer = 236.16 kJ/kg

Ratio of return velocity to inlet velocity = 0.80

Explanation:

Given

Temperature of liquid nitrogen, T1 = 90 K

Pressure of liquid nitrogen, P1 = 400 kPa

Temperature of nitrogen, T2 = 160 K

Pressure of nitrogen, T2 = 400 kPa

A(e) = 100 A(i)

To solve, we use the formula

h(i)+ 1/2v(i)² + q = h(e) + 1/2v(e)² + q

The mass flow is

m = m(i) = m(e)

m = (Av/V)i = (Av/V)e

Ratio of return velocity to inlet velocity is

v(e) / v(i) = A(i)/A(e) * V(e)/V(i)

v(e) / v(i) = 1/100 * V(e)/V(i)

From the saturated Nitrogen table, at 100 K, we have

h(i) = h(f) = -73.2

v(i) = v(f) = 0.001452

From the saturated Nitrogen table again, at 160 K and 400 kPa

h(e) = 162.96 kJ/kg

v(e) = 0.11647 m³/kg

Substituting these in the formula, we have

v(e) / v(i) = 1/100 * 0.11647/0.001452

v(e) / v(i) = 1/100 * 80.2

v(e) / v(i) = 0.80

Energy equation is given by

q + h(i) = h(e)

q = h(e) - h(i)

Now, calculating specific heat transfer

q = 162.96 - -73.2

q = 236.16 kJ/kg

6 0
3 years ago
Two basketballs of equal mass are rolling toward each other at constant velocities. The first basketball (B1) has a velocity of
slamgirl [31]

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

<u>Explanation:</u>

Velocity of B₁ = 4.3m/s

Velocity of B₂ = -4.3m/s

For perfectly elastic collision:, momentum is conserved

m_1v_1 + m_2v_2 = m_1v'_1 + m_2v'_2

where,

m₁ = mass of Ball 1

m₂ = mass of Ball 2

v₁ = initial velocity of Ball 1

v₂ = initial velocity of ball 2

v'₁ = final velocity of ball 1

v'₂ = final velocity of ball 2

The final velocity of the balls after head on elastic collision would be

v'_2 = \frac{2m_1}{m_1+m_2} v_1 - \frac{m_1-m_2}{m_1+m_2} v_2\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} v_1 + \frac{2m_2}{m_1+m_2} v_2

Substituting the velocities in the equation

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.

5 0
3 years ago
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