Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
Step-by-step explanation:
4x-9y=-9 1
2x +3y=3 2
1 - 2(2)
4x -9y=-9
(2)* -4x -6y=6
________
0-15y=-3
15y=3
y=3/15
y=1/5
The length and width of the fence should be made 76.25 feet and 23.75 feet respectively. Also, the expression for the length is L = 3W + 5 and the perimeter is P = 2(4W + 5).
<h3>How to determine the fence's dimension?</h3>
Mathematically, the perimeter of a rectangle can be calculated by using this formula;
P = 2(L + W)
<u>Where:</u>
- P is the perimeter of a rectangle.
- L is the length of a rectangle.
- W is the width of a rectangle.
Since the length of this fence is 5 more than 3 times the width, we have:
L = 3W + 5
Substituting the given parameters into the formula, we have;
200 = 2(3W + 5 + W)
200 = 2(4W + 5)
200 = 8W + 10
8W = 190
W = 190/8
W = 23.75 feet.
For the length, we have:
L = 3W + 5
L = 3(23.75) + 5
L = 76.25 feet.
Read more on perimeter of a rectangle here: brainly.com/question/17107023
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Answer:
Given that a polynomial has a constant term and at least one other term what is the minimum number of possible zero values based on the rational zero test? a-0 b-2 c-3 d-4
