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3 years ago

Solve for A? please hurry 115 45 10 25

Mathematics

2 answers:

andrew-mc [135]3 years ago

6 0

Answer:

25 degrees

Step-by-step explanation:

the angle is complementary which is when both angles add to 90 because it is a right angle do 90-65 which equals 25

zloy xaker [14]3 years ago

3 0

Answer:

Step-by-step explanation:

65+A=90

A=90-65=25

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Karina and Perry are cleaning up litter in the park for community service hours. Karina and Perry both claim they have covered t

alexgriva [62]

Answer:

Perry's claim is correct while Karina is incorrect

Step-by-step explanation:

Question is incomplete (See Attachment)

First, we need to determine the area covered by Karina and Perry

For Karina, there are 9 square boxes each of which has an area of 1 unit sq

So:

$Karina = 9 * 1\ unit^2$

$Karina = 9\ unit^2$

For Perry:

There are 18 square boxes, each of which has an area of 1 unit sq.

So:

$Perry = 18 * 1\ unit^2$

$Perry = 18\ unit^2$

Comparing both areas, we can conclude that Perry's claim is correct while Karina is incorrect

7 0

2 years ago

Isabella has a 22 ounce cola. She drinks 17 ounces. Enter the percentage of ounces Isabella has left of her cola. Round your ans

jenyasd209 [6]

Answer:

22.73% of ounces Isabella has left of her cola.

Step-by-step explanation:

Given:

Isabella has a 22 ounce cola. She drinks 17 ounces.

Now, to find the percentage of ounces Isabella has left of her cola.

Total ounces of cola = 22.

Ounces of cola Isabella drink = 17.

So, the ounces of cola she left:

Total ounces of cola - ounces of cola Isabella drink.

$=22-17$

$=5\ ounces.$

Thus, 5 ounces of cola she left.

Now, to get the percentage of cola she left:

$\frac{5}{22}\times 100$

$=\frac{500}{22}$

$=22.727\%.$

Rounding the percentage to the nearest hundredths is 22.73%.

Therefore, 22.73% of ounces Isabella has left of her cola.

7 0

3 years ago

In rhombus ABCD, DB=16 and AC=12. What is the perimeter of rhombus ABCD?

riadik2000 [5.3K]

DB+ DC= 32
AC+ AC =24
32+24
56

4 0

3 years ago

Camden is going to invest $600 and leave it in an account for 12 years. Assuming the

UkoKoshka [18]

$~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}$

$920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r$

7 0

2 years ago

Please Factor completely and explain thanks

Ivahew [28]

(4h+2)(2h+8)

4htines 2h= 8h^2
4htimes8=32h
2 times 2h=4h
2 times 8=16
Add Middle two you have
8h^2+36h+16

6 0

3 years ago

Read 2 more answers