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Elden [556K]
3 years ago
5

You're invited to a hot tub party! Being the science geek that you are, you decide to calculate the amount of mL in the 650.0 ga

llon hot tub!​
Chemistry
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

cool but can we have a little bit bigger

Explanation:

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What's the smallest celestial body
finlep [7]
Neutron Stars are considered as the smallest celestial bodies 
6 0
3 years ago
Calculate the molarity of 32.9 g32.9 g of MgS MgS in 971 mL 971 mL of solution.
Doss [256]

Answer:

0.60 M

Explanation:

Given data:

Mass of MgS = 32.9 g

Volume of solution = 971 mL (0.971 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of MgS:

Number of moles = mass/molar mass

Number of moles = 32.9 g/ 56.38 g/mol

Number of moles = 0.58 mol

Molarity of solution:

M = 0.58 mol/ 0.971L

M = 0.60 M

6 0
3 years ago
The volume of a single platinum atom is 1.12×10-23 cm3. what is the volume of a platinum atom in microliters?
Dvinal [7]
Basically, this problem asks you to convert units of volume from cm³ to μL. Cubic centimeters is the cubic volume equivalent of milliliters or mL. According to the metric system for L, microliter is 10⁻⁶ of a liter, while milliliter is 10⁻³ of a liter. Therefore, the solution is written as

(1.12×10⁻²³ cm³)*(1 mL/1 cm³)*(10⁻³ L/ 1 mL)*(1μL/10⁻⁶ L) = 1.12×10⁻²⁰ μL
4 0
3 years ago
Read 2 more answers
How many joules of heat are required to heat 25.0 g of isopropyl alcohol from the prevailing room temperature, 21.2 oC, to its b
valentinak56 [21]

Answer:

3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.

Explanation:

Q=m\times c\Delta T=m\times c\times (T_2-T_1)

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

T_1 = Initial temperature of the substance

T_2 = Final temperature of the substance

We have mass of isopropyl alcohol = m = 25.0 g

Specific heat of isopropyl alcohol  = c = 2.604 J/g°C

Initial temperature of the isopropyl alcohol = T_1=21.2^oC

Final temperature of the isopropyl alcohol = T_2=82.4 ^oC

Heat absorbed by the isopropyl alcohol to boil:

Q=25.0 g\times 2.604 J/g^oC\times (82.4^oC-21.2^oC)=3984.12 J

3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.

7 0
3 years ago
Calculate the Molarity when 14.6 g Ethanol (C2H5OH) is dissolved in a 2.10 L solution.
Nana76 [90]
The molarity is 0.151 mol/L
Hope it helps.
5 0
2 years ago
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