Answer:
5.758 is the density of the metal ingot in grams per cubic centimeter.
Explanation:
1) Mass of pycnometer = M = 27.60 g
Mass of pycnometer with water ,m= 45.65 g
Density of water at 20 °C = d =
1 kg = 1000 g


Mass of water ,m'= m - M = 45.65 g - 27.60 g =18.05 g
Volume of pycnometer = Volume of water present in it = V


2) Mass of metal , water and pycnometer = 56.83 g
Mass of metal,M' = 9.5 g
Mass of water when metal and water are together ,m''= 56.83 g - M'- M
56.83 g - 9.5 g - 27.60 g = 19.7 g
Volume of water when metal and water are together = v

Density of metal = d'
Volume of metal = v' =
Difference in volume will give volume of metal ingot.
v' = v - V


Since volume cannot be in negative .
Density of the metal =d'
=
Yesssssssssssssssssssssss
Answer:
Substances generate a smell when their molecules land on so-called olfactory neurones in our noses (which, for some things, is a pretty unpleasant thought). ... But this fails to explain why some molecules with similar shapes can smell completely different, while others with quite different shapes can have a similar scent.
Explanation:
I took chemistry
Answer:
Separation technique used to separate mud and water without heating:
<u>Sedimentation-Decantation</u>
<u></u>
Explanation:
<em>1.The settling of the heavier particle at the bottom when the container is left undisturbed is called </em><u><em>sedimentation.</em></u>
<u><em></em></u>
<u><em>In a mixture of Mud and water :</em></u>
In this process the heavy mud particles settle at the bottom due to their high density .
2. Decantation : It is the process of pouring out the upper clear layer of the light particles.
<u><em>In a mixture of Mud and water :</em></u>
The water is lighter and form a clear layer over the settled mud particles. Hence by decantation the clear water is poured into a clean separate container
Thus mud remain in the bottom and the mixture is separated
Answer:
Empirical formula is PNCl₂
Explanation:
Percent composition means that 100 g of compound has x g of each element.
In 100 g of compound x, we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl.
So, let's make some rules of three:
In 100 g of compound we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl
In 579.43 g of compound we have:
(579.43 . 26.73) / 100 = 155 g of P
(579.43 . 12.09) / 100 = 70 g of N
(579.43 . 61.18) / 100 = 354 g of Cl
Let's convert the mass of the elements in moles.
155 g of P / 30.97 g/mol = 5 P
70 g / 14 g/mol = 5 N
354 g / 35.45 g/mol = 10 Cl