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Reptile [31]
3 years ago
9

Carol views a specimen under the microscope and notices that it has no nucleus. What

Chemistry
1 answer:
Margaret [11]3 years ago
7 0

Answer:

Bacteria

Explanation:

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Which of the three kinds of radiation is dangerous to us and why?
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There is alpha, beta, and gamma radiation. Gamma radiation can damage our tissue and DNA. Alpha and Beta can deflected but even gamma radiation can somewhat pass through concrete. 
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In a similar way to oxidation-reduction reactions, half-reactions can be written for electrochemical reactions.
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Consider the following reaction: 2H2S (g) + 3O2 (g)  2SO2 (g) + 2H2O (g) If O2 was the excess reagent, 8.3 mol of H2S were cons
Ganezh [65]

1. The balanced equation tells us that 2 moles of H2S produce 2 moles of H2O.  

8.3 moles H2S x (2 moles H2O / 2 moles H2S) = 8.3 moles H2O = theoretical amount produced  

8.3 moles H2O x (18.0 g H2O / 1 mole H2O) = 149 g H2O produced theoretically  

% yield = (actual amount produced / theoretical amount) x 100 = (137.1 g / 149 g) x 100 = 91.8 % yield  

2. Calculate moles of each reactant.  

150.0 g N2 x (1 mole N2 / 28.0 g N2) = 5.36 moles N2  

32.1 g H2 x (1 mole H2 / 2.02 g H2) = 15.9 moles H2  

The balanced equation tells us that we need 3 moles of H2 to react with every 1 mole of N2.  

So if we have 5.36 moles N2, we need 3x that = 16.1 moles H2. Do we have that much available? No, just under at 15.9 moles. So H2 is the limiting reactant. At the end of the reaction there will be a little N2 left over.

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3 years ago
At STP, a sample of gas occupies 0.225 L. Calculate the volume of this gas at a pressure of 2.7 atm and a temperature of 320 K.
irinina [24]

Answer:

This new temperature is 97.7 mL

Explanation:

Step 1: Data given

Volume = 0.225 L

STP = 1 atm and 273 K

Pressure = 2.7 atm

Temperature = 320 K

Step 2: Calculate new volume

(P1*V1)/T1 = (P2*V2)/T2

⇒with  P1 = the pressure at STP = 1 atm

⇒with V1 = the volume = 0.225 L

⇒with T1 = the temperature at STP = 273 K

⇒with P2 = the new pressure = 2.7 atm

⇒with V2 = the new volume  = TO BE DETERMINED

⇒with T2 = the new temperature = 320 K

(1atm *0.225 L)/273 K = (2.7 atm * V2) /320 K

8.24 * 10^-4 = 2.7 * V2 / 320K

2.7V2 = 0.264

V2 = 0.0977 L = 97.7 mL

This new temperature is 97.7 mL

8 0
3 years ago
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