Answer:
1. 4m(note this might be switched with 2)
2. 5m(note this might be switched with 1)
3.3m
4. 60
5.60
Step-by-step explanation:
Answer:
7.64% probability that they spend less than $160 on back-to-college electronics
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Probability that they spend less than $160 on back-to-college electronics
This is the pvalue of Z when X = 160. So
has a pvalue of 0.0763
7.64% probability that they spend less than $160 on back-to-college electronics
Answer:
x=17
Step-by-step explanation:
This should be for a "kite": AD=DC, AB=BC and ∠A=∠C
8x-27 = 3x+58
5x = 85
x = 17
Answer : A it is decreased by $70,000
Federal reserve sells $70,000 in treasury bonds to a bank.
Removing cash decreases the money supply . Money supply decreases when exchanging for bonds. That is the immediate effect on money supply.
Federal reserve sells $70,000 . so money supply is decreased by $70,000
In your question where ask to find the Standard Normal Distribution of the following:
give probabilities for 0<Z<infinity.
For these ranges, you can read directly, for example,
P(Z<1.96)=0.975.
So for #1, you read directly on the line 1.3 and column 0.03.
For #2, we note that the distribution is symmetrical about Z=0, so
P(Z<-2.33) is the same as P(Z>2.33)
which again is the same as
1-P(Z<2.33) because we know that the area under a probability distribution function adds up to 1.
For the remaining questions, work is similar to #2.
