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AlekseyPX
3 years ago
10

What is NASA currently considering as possible ways to decrease the impact of radiation during longer space missions?

Physics
2 answers:
Colt1911 [192]3 years ago
8 0

The correct answer to this open question is the following.

As complicated Missions such as the ones to Planet Mars are prepared, NASA is currently considering possible ways to decrease the impact of radiation during longer space missions.

Planet Mars doesn't have a global magnetic field to defect energetic particles, so astronauts have to protect from Sun's radiation and galactic cosmic rays radiation. The two types of protection that NASA is devising are, the use of more mass of traditional material to build the spacecraft and the use of more efficient shields, and for this, NASA needs to invest more money to find the right kind of material that can add protection to the shields.

xz_007 [3.2K]3 years ago
3 0

One category mentioned was creating an advanced, new radiation shielding. Problem with new shielding is that it has weight associated with it. The added weight could cause problems on a long space mission.

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Hi, I am having issues with this physics question. I find it quite complicated to solve and I don't even have the answer to this
galina1969 [7]

Answer:

200 m

Explanation:

Both Jerry and Tom start at the end of the pipe where the cheese is.  Jerry then runs into the pipe at 20 m/s while Tom chases him at 10 m/s.  When Jerry reaches the other end of the pipe, where Tom's cousin is, he turns around.  Eventually, he reaches Tom again, so he turns around again.  This continues until both Tom and Jerry reach the end of the pipe where Tom's cousin is.

We need to find the distance traveled by Jerry.  We already know Jerry's speed, so we just need to find the time.  We can do that using Tom's speed and the length of the pipe.

x = vt

100 m = (10 m/s) t

t = 10 s

So both Tom and Jerry run for 10 seconds.  Since Jerry runs at a speed of 20 m/s, the distance he travels is:

x = vt

x = (20 m/s) (10 s)

x = 200 m

Jerry runs a distance of 200 meters.

8 0
3 years ago
How does the movement of particles of matter change when temperature decreases
Zanzabum
INCREASE in temperature of the material practically increase the energy of the particles. which increases their motion due to increase in energy . thus when the temperature is decreased the energy level decreases which causes the particle's motion to slow down.. the motion of the particle is highly reduced when the temperature is lowered
4 0
4 years ago
What is your volume of the object?<br> 30 cm3<br> 35 cm3<br> 42 cm3<br> 54 cm3
Alinara [238K]
The answer is 54 cm3
3 0
3 years ago
Why does jupiter have several distinct cloud layers?
pentagon [3]

Different layers represent clouds made of gases that condense at different temperatures.

4 0
3 years ago
Suppose you have two solid bars, both with square cross-sections of 1 cm2. They are both 24.6 cm long, but one is made of copper
vodka [1.7K]

Explanation:

Expression to calculate thermal resistance for iron (R_{I}) is as follows.

             R_{I} = \frac{L_{I}}{k_{I} \times A_{I}}  

where,   L_{I} = length of the iron bar

             k_{I} = thermal conductivity of iron

             A_{I} = Area of cross-section for the iron bar

Thermal resistance for copper (R_{c}) = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]

where,  L_{c} = length of copper bar

             k_{c} = thermal conductivity of copper

            A_{c} = Area of cross-section for the copper bar

Now, expression for the transfer of heat per unit cell is as follows.

           Q = \frac{(100^{o} - 0^{o}}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

 Putting the given values into the above formula as follows.

       Q = \frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

  = \frac{(100^{o} - 0^{o})}{21 \times 10^{-2} m[\frac{1}{73 \times 10^{-4}m^{2}} + \frac{1}{386 \times 10^{-4}m^{2}}}

           = 2.92 Joule

It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,

                 P = \frac{Q}{T}

Here, T is 1 second so, power conducted is equal to heat transferred.

So,           P = 2.92 watt

Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.

7 0
3 years ago
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