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Nookie1986 [14]
3 years ago
7

An object is launched with an initial speed of 30 m/s at an angle of 60° above the horizontal . What is the maximum height reach

ed by the object
Physics
1 answer:
matrenka [14]3 years ago
6 0

Answer:

H = 34.43 m

Explanation:

Given that,

Initial speed of the object, u = 30 m/s

The angle of projection, \theta=60^{\circ}

We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(30)^2\times \sin^2(60)}{2\times 9.8}\\\\H=34.43\ m

So, the maximum height reached by the object is 34.43 m.

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