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hichkok12 [17]
3 years ago
15

The variables for this experiment include mass, volume and the materials in the various balls, as well as their densities. In Pa

rt II, you will be comparing an inflated football with a deflated one. Use the drop-down menus to complete the sentences and identify the independent and dependent variables. In Part II, the independent variable, the one that is intentionally manipulated, is
Physics
2 answers:
gayaneshka [121]3 years ago
8 0

Answer:

part 1 is mass

Explanation:

i just got it rong then it gave me the  answer and it said mass

Natalija [7]3 years ago
5 0

FOR PART 3!!!! THIS IS THE ANSWER


The variables for this experiment include mass, volume and the materials in the various balls, as well as their densities. In Part III, you will be investigating the questionable baseball. Use the drop-down menus to complete the sentences and identify the independent and dependent variables

MATERIAL

DENSITY

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Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m  = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \  \times \ \ \ \ 1   \ lbf\ }

m  = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm

Therefore, the mass of the object is 5.045 lbm.

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