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3 years ago

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An acid is a compound that produces the __ ion in solution, which is also written as the hydronium ion _ . A base is a c

ompound that produces an ion with the formula ______ and the name _______ ion.

1 answer:

VMariaS [17]3 years ago

4 0

Answer:

An acid is substance that produces <u>H⁺ </u>ions in solution, which is also written as the hydronium ion <u>H₃O⁺</u>. A base is a substance that produces an ion with the formula <u>OH⁻ </u>and the name <u>hydroxyl</u> ion.

Explanation:

An acid is substance that produces H⁺ ions in solution, which is also written as the hydronium ion H₃O⁺. A base is a substance that produces an ion with the formula OH⁻ and the name hydroxyl ion.

Acid:

An acid is the substance that sour in taste and turns the color of litmus paper from blue to red.

pH of acid is less than seven.

Base:

An acid is the substance that bitter in taste and turns the color of litmus paper from red to blue.

The pH of base is 7-14.

Arrhenius gives the simplest definition of acid and base.

Arrhenius acid:

A substance that increase the concentration of hydronium ion in solution is called acid.

HNO₃ → H⁺ + NO₃⁻

(H₂O)

Arrhenius base:

A substance that increase the concentration of OH⁻ ion in solution is called base.

KOH → K⁺ + OH⁻

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A balloon containing N2 has 1.70 moles and occupies 3.80L. What will the volume be if the number of moles is increased to 2.60mo

leonid [27]

Answer:

5.81L

Explanation:

N1 = 1.70 moles

V1 = 3.80L

V2 = ?

N2 = 2.60 moles

Mole - volume relationship,

N1 / V1 = N2 / V2

V2 = (N2 × V1) / N1

V2 = (2.60 × 3.80) / 1.70

V2 = 9.88 / 1.70

V2 = 5.81 L

The volume of the gas is 5.81L

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3 years ago

The compound AlP (aluminum phosphide) is a compound semiconductor having mixed ionic and covalent bonding. Calculate the fractio

netineya [11]

Answer:

0.086

Explanation:

The formula for calculating the fraction of a covalent bond can be expressed as:

= exp (-0.25ΔE²)

$= exp[-0.25(E_{Al}-E_{p})^2]---(1)$

from the equation above;

$E_{Al}$ = the electronegativity of aluminum

$E_P$ = electronegativity of phosphorus

Using the data from periodic table figures;

$E_{Al}$ = 1.5

$E_P$ = 2.1

∴

fraction of the covalent = exp[-0.25(1.5 - 2.1)²]

fraction of the covalent = exp(-0.09)

fraction of the covalent = 0.914

Now, the fraction of ionic bond will be = 1 - the fraction of covalent bond

= 1 - 0.914

∴

the fraction of bond that is ionic = 0.086

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3 years ago

What is the chemical formula for ammonia sulfide

Mandarinka [93]

Answer:

(NH4)2S

Explanation:

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3 years ago

CORRECT ANSWER GETS BRAINLIEST! PLEASE HELP AND EXPLAIN!!

Anna71 [15]

Answer:

A car stopped at the top of the hill

Explanation:

It's potenial energy because, the car could go down the hill and create kinetic energy. Hope this helps! Please give me brainly it is correct!

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3 years ago

Sunflower oil contains 0.080 mol palmitic acid (C16H32O2)/mol, 0.060 mol stearic acid (C18H36O2)/mol, 0.27 mol oleic acid (C18H3

Cerrena [4.2K]

Answer:

$x_H=0.882$

$x_N=0.118$

Explanation:

In this reactor, oleic and linoleic acid react with hydrogen to form stearic acid. This reactions can be represented by:

Oleic: $C_{18}H_{34}O_2 (l) + H_2 (g) \longrightarrow C_{18}H_{36}O_2 (l)$

Linoleic: $C_{18}H_{32}O_2 (l) + 2 H_2 (g) \longrightarrow C_{18}H_{36}O_2 (l)$

Having this reactions in mind, the first thing is to determine the moles of hydrogen required:

<u>Base of caculation: 1 mol of sunflower oil</u>

For oleic acid: $n_{Holeic}=\frac{1 mol H_2}{1 mol oleic}*\frac{0.27 mol oleic}{1 mol oil}*\frac{335 mol oil}{hr}$

$n_{Holeic}=frac{90.45 mol H_2}{hr}$

For linoleic acid: $n_{Hlinoleic}=\frac{2 mol H_2}{1 mol linoleic}*\frac{0.59 mol linoleic}{1 mol oil}*\frac{335 mol oil}{hr}$

$n_{Holeic}=frac{395.3 mol H_2}{hr}$

$n_{Htotal}=\frac{90.45 mol H_2}{hr}+\frac{395.3 mol H_2}{hr}$

$n_{Htotal}=frac{485.75 mol H_2}{hr}$

Applying the excess:

$n_{Htotal}=frac{485.75 mol H_2}{hr}*1.65=801.48 mol$

Nitrogen: $n_N= 801.48 mol*\frac{0.05 mol N}{0.95 mol}$

$n_N= 42.2 mol N$

<u>After the reactions</u>:

$n_H=801.48 mol-485.75mol=315.73 mol$

and the nitrogen is inert.

Purge stream:

$n_total=42.2+315.73 mol=357.93 mol$

$x_H=\frac{315.73mol}{357.93mol}=0.882$

$x_N=\frac{42.2mol}{357.93mol}=0.118$

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3 years ago