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muminat
3 years ago
5

Could you use naoh to separate aspirin and acetaminophen by acid base extraction

Chemistry
1 answer:
Ksivusya [100]3 years ago
4 0

if you are careful. aspirin is strongly acidic and tylenol is weakly acidic. if you split the difference between the two, you can deprotonate aspirin without deprotonating tylenol. more specifically, if you use NaOH to raise the pH of a solution to approximately 7 or 8, you could effectively deprotonate all of the aspirin, making it water soluble, while leaving the tylenol protonated and not very water soluble. if the pH goes above 10, you will deprotonate the tylenol and make them both water soluble. HOPE THIS HELPED :)
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1. If Susan reproduced asexually what would be the outcome if she had offspring? What would they look like?​
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They would look exactly like her, when you produce asexually your offspring is a clone of you. The offspring is genetically identical to the parent.

Explanation:

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3 years ago
What is the volume of 0.2 moles of neon gas at STP?
eduard

Standard Molar Volume is the volume occupied by one mole of any gas at STP. Remember that "STP" is Standard Temperature and Pressure. Standard temperature is 0 &176:C or 273 K. Standard pressure is 1 atmosphere or 760 mm Hg (also called "torr"). 1 mole of any gas at STP occupies 22.4 liters of volume.

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Read 2 more answers
How to find hydrogen ion concentration from molarity of solution
vekshin1

The concentration of the hydrogen ions from molarity can be given with the number of hydrogen atoms in the molecular formula.

<h3>What is molarity?</h3>

Molarity is given as the moles of the solute present in a liters of solution. The compound with the number of hydrogen atoms in the molecular formula with degradation possesses the equivalent concentration of the hydrogen ions.

The compound with molecular formula AH having molarity 2, will produce 2M of hydrogen ions.

Learn more about molarity, here:

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7 0
2 years ago
Pls that is the picture ​
Fiesta28 [93]
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3 0
3 years ago
By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm
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The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

\tt 0.943~L=0.943\times 10^{-3}m^3

Volume of oil dumped = volume of swimming pool

\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}

3 0
3 years ago
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