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muminat
3 years ago
5

Could you use naoh to separate aspirin and acetaminophen by acid base extraction

Chemistry
1 answer:
Ksivusya [100]3 years ago
4 0

if you are careful. aspirin is strongly acidic and tylenol is weakly acidic. if you split the difference between the two, you can deprotonate aspirin without deprotonating tylenol. more specifically, if you use NaOH to raise the pH of a solution to approximately 7 or 8, you could effectively deprotonate all of the aspirin, making it water soluble, while leaving the tylenol protonated and not very water soluble. if the pH goes above 10, you will deprotonate the tylenol and make them both water soluble. HOPE THIS HELPED :)
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How is electronegativity used in determining the ionic or covalent character of the bonding between two elements?
madam [21]

Answer:

If the electronegativity difference between bonded atoms are too much high ionic bonds are formed if the electronegativity diference is 0.4 or less than 0.4 non polar covalnet bond formed the difference greater than 0.4 polar covalent bond formed.

Explanation:

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

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3 years ago
While estimating the Caloric content of the chemical constituents present in the food item, the carbohydrate amount is discounte
Mashcka [7]

Answer:

Fiber is "Not Digestible"

Explanation:

Carbohydrates that contain fiber cannot be completely digested. the indigestible components of fiber are measured in the calorimeter, but they are not accessible for energy in the human body.

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2 years ago
A hot cup of water has fewer molecules than a hot tub of water. This same cup of
Mrac [35]

Answer:eeded to change the temperature of one gram of a substance one degree ... iron(specific heat=0.12 cal/g C) and a cup of water both have the same temperature. ... If you drop a hot rock into a pail of water,the temperature of the rock and the water ... Therefore, water molecules have higher specific heat capacity than metals

Explanation:

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A chemist dissolves 867. mg of pure barium hydroxide in enough water to make up 170. mL of solution. Calculate the pH of the sol
Ilya [14]

Answer: The pH of the solution is 11.2

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of Ba(OH)_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{0.867g}{171g/mol}=0.00507mol         (1g=1000mg)

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.00507\times 1000}{170}

Molarity=0.0298

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pOH=-\log [OH^-]

Ba(OH)_2\rightarrow Ba^{2+}+2OH^{-}

According to stoichiometry,

1 mole of Ba(OH)_2 gives 2 mole of OH^-

Thus 0.0298 moles of Ba(OH)_2 gives =\frac{2}{1}\times 0.0298=0.0596 moles of OH^-

Putting in the values:

pOH=-\log[0.0596]=2.82

pH+pOH=14

pH=14-2.82

pH=11.2

Thus the pH of the solution is 11.2

8 0
3 years ago
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