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Molodets [167]
3 years ago
8

Using the projectiles equations for y and x at what second does the ball have a vertical velocity of -39.2 m/s^2

Physics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

<h2>a) t = 4</h2>

Explanation:

In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).

tmax = Usin\theta/g

U = velocity of the ball

\theta = angle of projection = 90° (vertical velocity)

g = acceleration due to gravity = 9.8m/s²

tmax = Usin90°/9.8

tmax = U/9.8

T the maximum height U = Uy =  39.2 m/s²

tmax = 39.2/9.8

tmax = 4secs

To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but \theta will be 0° in this case

If Ux = Ucos\theta

8 = Ucos0

U = 8m/s

Since t = Usin\theta/g

t = 8sin0/9.8

t = 0sec

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The answer to that will be the Troposphere.
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A mass of 3.6 kg oscillate on a horizontal spring with a spring constant of 160 N/m.
Darya [45]

Answer:

48.7 J

Explanation:

For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.

In particular:

- The elastic potential energy is maximum when the system is at its maximum displacement

- The kinetic energy is maximum when the system passes through the equilibrium position

Therefore, the maximum kinetic energy of the system is given by:

KE=\frac{1}{2}mv^2

where

m is the mass

v is the speed at equilibrium position

In this problem:

m = 3.6 kg

v = 5.2 m/s

Therefore, the maximum kinetic energy is:

KE=\frac{1}{2}(3.6)(5.2)^2=48.7 J

6 0
3 years ago
Consider an oblique shock wave with a wave angle of 35 o . Upstream of the wave, the static pressure and temperature are 2,000 l
ziro4ka [17]

Answer:

The pressure is 6570  lbf/ft²

The temperature is 766 ⁰R

The velocity is 2746.7 ft/s

deflection angle behind the wave is 17.56⁰

Explanation:

Speed of air at initial condition:

a_1 = \sqrt{\gamma RT } =  \sqrt{1.4* 1716*520 } = 1117.70 \ ft/s

γ is the ratio of specific heat, R is the universal gas constant, and T is the initial temperature.

initial mach number

M_1 = \frac{v_1}{a_1} = \frac{3355}{1117.7}  = 3

then, M_n = M_1sin \beta = 3sin(35) = 1.721

based on the values obtained, read off the following from table;

P₂/P₁ = 3.285

T₂/T₁ = 1.473

Mₙ₂ = 0.6355

Thus;

P₂ = 3.285P₁ = 3.285(2000) = 6570  lbf/ft²

T₂ = 1.473T₁ = 1.473(520⁰R) = 766 ⁰R

Again; to determine the velocity and deflection angle, first we calculate the mach number.

M_t_1 = M_1cos \beta = 3 cos(35) = 2.458

w_2 = a_1M_t_1 = 2.458(1117.70) = 2746.7 \ ft/s

a_2 = \sqrt{\gamma RT_2} = \sqrt{1.4*1718*766} = 1357.34 \ ft/s

v_2 = a_2M_n_2 = 1357.34(0.6355) = 862.59 \ ft/s

Tan(\beta -\theta) = \frac{v_2}{w_2} = \frac{862.59}{2746.7}  \\\\Tan(\beta -\theta) = 0.314\\\\\beta -\theta= 17.44\\\\\theta = \beta - 17.44 = 17.56^o

6 0
3 years ago
Assume that you can heat water with perfect insulation (all the heat from combustion of ethanol is transferred to water). What i
krok68 [10]

Answer:

volumme =0.36 ml

Explanation:

total heat required can be obtained by using following formula

q= mC \Delta T.......(1)

where,

m - mass of water,

C - specific heat capacity of water and = 4.184 j g^{-1} °C

\Delta T - total change in temperature.  = 10°C

The density of water is 1 g/cc. hence, 200 mL of water is equal to 200 g

putting all value in the above equation (1)

q = 200*4.184* 10 ° = 8368 J.

Therefore total number of moles of ethanol required to supply 8368 J of heat is

\frac {8368}{1368000} = 0.006117 moles.

The molar mass of ethanol is 46 g/mol.

The mass of ethanol required is 46* 0.006117 = 0.28138 g

The density of ethanol is 0.78 g/ml.

The volume of ethanol required is

\frac {0.28138}{0.78} = 0.36 ml

8 0
3 years ago
if i roll pieces of allium foil in a ball what property of aluminium foil changes as a result of my action​
MArishka [77]

Answer:

Malleability

Explanation:

The ability to roll aluminum foil in a ball is the property of metal called malleability.

  • Metallic bonds in metals makes it possible for them to take different shape without losing internal cohesion.
  • Metals are malleable and they posses a wide range of physical properties.
  • A malleable metal can be beaten into sheets and molded into many shapes.
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