Using the projectiles equations for y and x at what second does the ball have a vertical velocity of -39.2 m/s^2
1 answer:
Answer:
<h2>a) t = 4</h2>Explanation:
In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).
tmax = Usin/g
U = velocity of the ball
= angle of projection = 90° (vertical velocity)
g = acceleration due to gravity = 9.8m/s²
tmax = Usin90°/9.8
tmax = U/9.8
T the maximum height U = Uy = 39.2 m/s²
tmax = 39.2/9.8
tmax = 4secs
To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but will be 0° in this case
If Ux = Ucos
8 = Ucos0
U = 8m/s
Since t = Usin/g
t = 8sin0/9.8
t = 0sec
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