Answer:
<h2>a) t = 4</h2>Explanation:
In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).
tmax = Usin/g
U = velocity of the ball
= angle of projection = 90° (vertical velocity)
g = acceleration due to gravity = 9.8m/s²
tmax = Usin90°/9.8
tmax = U/9.8
T the maximum height U = Uy = 39.2 m/s²
tmax = 39.2/9.8
tmax = 4secs
To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but will be 0° in this case
If Ux = Ucos
8 = Ucos0
U = 8m/s
Since t = Usin/g
t = 8sin0/9.8
t = 0sec
Answer:
The minimum uncertainty in its speed is greater than .
Explanation:
It is given that,
Speed of the particle,
We need to find the minimum uncertainty in its speed. It can be calculated using uncertainty principle as :
Since, p = mv
So, the minimum uncertainty in its speed is greater than . Hence, this is the required solution.
Answer:
1.33
Explanation:
For an optical instrument, the magnification ratio of the apparent diameter of the image to that of the object.
Mathematically, from the given information;
Magnification
where;