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3 years ago

Most radiation exposure comes from

2 answers:

5 0

Most radiation exposure comes from natural sources. These so-called "natural sources" include Radon, Internal, Terrestrial, and Cosmic. Among that, Radon proves to be the largest source of radiation. Radon is a naturally occurring radioactive gas that comes from the breakdown of uranium.

Yuliya22 [10]3 years ago

3 0

Answer:

d. natural source

Explanation:

When energy is emitteds by a source and travels through a medium until it's absorbed by matter, radiation is occuring. We are exposed to radiation everyday, some sources of radiation are natural and other come from man-made elements. We are commonly exposed to Background radiation, from Earth itself (some minerals) and very few man-made objects. From this type of radiation comes the one we are the most exposed to emitted by Radon and Thoron (radioactive gases which are created when other naturally occurring elements undergo radioactive decay). This gases represent 37% of all the radiation we are commonly exposed to.

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Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.00×104 Pa . Assum

cestrela7 [59]

Answer:

$T_{2}=278.80 K$

Explanation:

Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.

$(\frac{V_{1}}{V_{2}})^{\gamma -1} = \frac{T_{2}}{T_{1}}$ .

Now, let's use the ideal gas equation to the initial and the final state:

$\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}$

Let's recall that the term nR is a constant. That is why we can match these equations.

We can find a relation between the volumes of the initial and the final state.

$\frac{V_{1}}{V_{2}}=\frac{T_{1}p_{2}}{T_{2}p_{1}}$

Combining this equation with the first equation we have:

$(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}$

$(\frac{p_{2}}{p_{1}})^{\gamma -1} = \frac{T_{2}^{\gamma}}{T_{1}^{\gamma}}$

Now, we just need to solve this equation for T₂.

$T_{1}\cdot (\frac{p_{2}}{p_{1}})^{\frac{\gamma - 1}{\gamma}} = T_{2}$

Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.

Here,

$p_{2}=8.00\cdot 10^{4} Pa \\p_{1}=1.01\cdot 10^{5} Pa\\ T_{1}=298 K\\ \gamma=1.40$

Finally, T2 will be:

$T_{2}=278.80 K$

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3 years ago

On a cross-country trip, a couple drives 500 mi in 10 h on the first day, 380 mi in 8.0 h on the second day, and 600 mi in 15 h

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We know that the average speed is simply the ratio of the total distance travelled over the total duration of the trip.

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total time = 33 h

So the average speed is therefore:

average speed = 1,480 mi / 33 h

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A scientist claimed that fabric A is better able to resist fire than fabric B. Which option describes an experiment that will pr

UNO [17]

Answer:

B. Hold each type of fabric over a candle flame and time how long it takes for the fabric to start to burn.

Explanation:

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Akio draws the ray diagram shown.

Inessa [10]

Answer: Move the small car so it appears on the left side of the lens.

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