Swept-frequency pulses have found use in a variety of fields, including spectroscopic methods where effective spin control is necessary.
To find more, we have to study about the spectroscopic methods.
<h3>
What is homonuclear decoupling and broadband excitation?</h3>
- A thorough understanding of the evolution of spin systems during these pulses is crucial for many of these applications since it not only helps to describe how procedures work but also makes new methodologies possible.
- Broadband inversion, refocusing, and excitation employing these pulses are some of the most popular applications in NMR, ESR, MRI, and in vivo MRS in magnetic resonance spectroscopy.
- A generic expression for chirped pulses will be presented in this study, along with numerical methods for calculating the spin dynamics during chirped pulses using solutions along with extensive examples.
Thus, we can conclude that, the swept-frequency pulses have found use in a variety of fields, including spectroscopic methods where effective spin control is necessary.
Learn more about the broadband excitation here:
brainly.com/question/19204110
#SPJ4
(a) Intensity obeys inverse square law from basis of light passing through a given surface.
(b) Gravitation obeys inverse square law from the basis of force between two masses.
(c) The maximum magnitude of the acceleration of the block is 126.75 m/s².
<h3>
What is intensity?</h3>
Intensity is the ratio is ratio of power to area of a given surface.
I = P/A (W/m²)
where;
<h3>Universal gravitation law</h3>
Intensity and gravitation do not obey inverse square law for same reason;
- Intensity obeys inverse square law from basis of light passing through a given surface.
- Gravitation obeys inverse square law from the basis of force between two masses.
<h3>Acceleration of the block</h3>
a = v²/A
a = (3.9²)/0.12
a = 126.75 m/s²
Learn more about acceleration here: brainly.com/question/605631
#SPJ1
No.
The acceleration of gravity on or near Earth's surface is 9.8 m/s² ,
not 20 m/s² .
If it were 20 m/s², then you would weigh almost exactly double
what you really weigh now.
Answer:
9.412 rad/s.
Explanation:
Velocity is the rate of change of an object's position.
V = x/t
Where x is the distance in m
= 2.4 m
t is time taken in s
= 8.5 s
V = 2.4/8.5
= 0.2824 m/s.
Equating linear velocity and angular velocity,
V = ω*r
Where,
ω Is the angular speed in rad/s
r is the radius of the circle in m
= 3 cm
= 3cm * 1m/100 cm = 0.03 m
ω = V/r
= 0.2824/0.03
= 9.412 rad/s.
Answer:
cardiovascular endurance
Explanation:
In order for Tom to successfully complete the marathon, he should focus on being able to maintain a constant pace without tiring easily.
