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statuscvo [17]
4 years ago
8

Most radiation exposure comes from

Physics
2 answers:
Mrrafil [7]4 years ago
5 0
Most radiation exposure comes from natural sources. These so-called "natural sources" include Radon, Internal, Terrestrial, and Cosmic. Among that, Radon proves to be the largest source of radiation. Radon is a naturally occurring radioactive gas that comes from the breakdown of uranium.
Yuliya22 [10]4 years ago
3 0

Answer:

d. natural source

Explanation:

When energy is emitteds by a source and travels through a medium until it's absorbed by matter, radiation is occuring. We are exposed to radiation everyday, some sources of radiation are natural and other come from man-made elements. We are commonly exposed to Background radiation, from Earth itself (some minerals) and very few man-made objects. From this type of radiation comes the one we are the most exposed to emitted by Radon and Thoron (radioactive gases which are created when other naturally occurring elements undergo radioactive decay). This gases represent 37% of all the radiation we are commonly exposed to.

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Particles 1 and 2 of charge q1 = q2 = +3.20 × 10−19 C are on a y axis at distance d = 17.0 cm from the origin. Particle 3 of cha
mel-nik [20]

Answer:

(a) 0.17 m

(b) 5.003 m

(c) 6.38 × 10^{-26} N

(d) 7.37 ×10^{-29} N

Explanation:

(a) The minimum value of x will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the <em>minimum value of x= 0.17 m</em>.

(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.

h^{2} = b^{2} + p^{2}

h^{2} = 5^{2} + 0.17^{2}   \\h = \sqrt{} 25.03\\h= 5.002 m

<em>Hence, the maximum distance is 5.002 m</em>

(c) For minimum magnitude we use the minimum distance calculated in (a)

Minimum Distance = 0.17 m

For electrostatic force=     F=\frac{kq1q2}{x^{2} }

F=\frac{9 x 10^{9} x3.2x10^{-19}x 6.4x10^{-19}  }{0.17^{2} }

F= 6.38×10^{-26} N

(d) For maximum magnitude, we use the maximum distance calculated in (b)

Maximum Distance = 5.002 m

Using the formula for electrostatic force again:

F =  \frac{9x10^{9}x3.2x10^{-19}x6.4x10^{-19}   }{5.002^{2} } }

F= 7.37×10^{-29 N

4 0
3 years ago
78. A particle moves along the x- axis. The velocity of the particle at time tis given by 4vt()=3 t +1 . If the position of the
RoseWind [281]

Explanation:

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3 years ago
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Answer:

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Explanation:

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6 0
3 years ago
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A grape is thrown straight up in the air. If it was thrown at 2 m/s, how high will it go in the air?
ser-zykov [4K]

Answer:

Answer: <u>Height</u><u> </u><u>is</u><u> </u><u>0</u><u>.</u><u>2</u><u>0</u><u>4</u><u> </u><u>m</u>

Explanation:

At the highest point, it is called the maximum height.

• From third newton's equation of motion:

{ \rm{ {v}^{2}  =  {u}^{2}  + 2gs}}

• At maximum height, v is zero

• u is initial speed

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{ \rm{0 {}^{2}  =  {2}^{2}   -  (2 \times 9.8 \times s)}} \\  \\ { \rm{4 = 19.6s}} \\  \\ { \rm{s = 0.204 \: m}}

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