1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
statuscvo [17]
3 years ago
8

Most radiation exposure comes from

Physics
2 answers:
Mrrafil [7]3 years ago
5 0
Most radiation exposure comes from natural sources. These so-called "natural sources" include Radon, Internal, Terrestrial, and Cosmic. Among that, Radon proves to be the largest source of radiation. Radon is a naturally occurring radioactive gas that comes from the breakdown of uranium.
Yuliya22 [10]3 years ago
3 0

Answer:

d. natural source

Explanation:

When energy is emitteds by a source and travels through a medium until it's absorbed by matter, radiation is occuring. We are exposed to radiation everyday, some sources of radiation are natural and other come from man-made elements. We are commonly exposed to Background radiation, from Earth itself (some minerals) and very few man-made objects. From this type of radiation comes the one we are the most exposed to emitted by Radon and Thoron (radioactive gases which are created when other naturally occurring elements undergo radioactive decay). This gases represent 37% of all the radiation we are commonly exposed to.

You might be interested in
When white light is viewed through sodium vapor in a spectroscope the spectrum is continuous?
elena-14-01-66 [18.8K]
<span>It's continuous except for a pair of dark lines.
They are very close together in the yellow/orange section of the spectrum.</span>
4 0
3 years ago
Read 2 more answers
Define frequency in terms of a wave
ElenaW [278]

Answer:

Explanation:

For a wave, the speed is the distance traveled by a given point on the wave (such as a crest) in a given period of time. So while wave frequency refers to the number of cycles occurring per second, wave speed refers to the meters traveled per second

7 0
3 years ago
a car with a mass of 1200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. the centrip
qaws [65]
Well, first of all, a car moving around a circular curve is not moving
with uniform velocity.  The direction of motion is part of velocity, and
the direction is constantly changing on a curve.

The centripetal force that keeps an object moving in a circle is

         Force  =  (mass of the object) · (speed)² / (radius of the circle)

         F  =  m s² / r

We want to know the radius, to rearrange the formula to give us
the radius as a function of everything else.

                                          F     =  m s² / r

Multiply each side by 'r':       F· r  =  m · s²

Divide each side by 'F':            r  =  m · s² / F    

We know all the numbers on the right side,
so we can pluggum in:

                      r  =       m       ·        s²      /     F

                      r  =  (1200 kg) · (20 m/s)² / (6000 N) .

I'm pretty sure you can finish it up from here.

                                      


5 0
3 years ago
A ball is thrown down vertically with an initial speed of v0 from a height of h. (a) What is its speed just before it strikes th
Alexus [3.1K]

Answer:

a)   v² = v₀² + 2 g h,  b)   t = v₀/g  (1+ √ (1 + 2gh/ v₀²))

Explanation:

a) This is an exercise that we can solve using conservation of energy.

Starting point. High point

         Em₀ = K + U = ½ m v₀² + m gh

Final point. Soil

         Em_{f} = K = ½ m v²

energy is conserved because there is no friction

         Emo = Em_{f}

         ½ m v₀² + m g h = ½ m v²

         v² = v₀² + 2 g h

b) the time it takes to reach the ground can be calculated with kinematics

let's create a reference frame with positive upward direction

         v = vo - g t

when it reaches the ground it has a velocity v, the initial velocity is downwards v₀ = -v₀

        v = -v₀ - gt

        t = - (v + v₀) / g

we substitute the velocity values ​​calculated in the previous part

        t = - (√(v₀² + 2 g h) + vo) / g

we will simplify the equation a bit

        t = - v₀/g  (1+ √ (1 + 2gh/ v₀²))

c) is now thrown vertically upward with the same initial velocity vo.

   To find the final velocity we use the conservation of energy where the velocity is squared, so it does not matter if it is positive or negative, therefore in this section the value should be the same as in part a

         v = √ (v₀² + 2gh)

d) for this part if there is change since the speed is not squared

     v₀ = v₀

          v = v₀ - gt

          t = (v₀ - v) / g

          t = (v₀ - √(v₀² + 2 g h)) / g

          t = v₀/g   (1 - √(1 + 2gh / v₀²))

3 0
2 years ago
How much work is accomplished when a force of 300N pushes a box across the floor for a distance of 100 meters?
Nesterboy [21]

So the correct ans is B.

hope it helps u.

5 0
3 years ago
Read 2 more answers
Other questions:
  • How do you find Net Force?
    15·2 answers
  • Which statement is true about the difference between calcium carbonate and calcium oxide?
    12·1 answer
  • Give an example from sport where at least 3 fundamental skills are linked together, name the movement action and name the three
    15·1 answer
  • E4.Suppose Galileo’s pulse rate was 75 beats per minute. How many beats per second is this? What is the time in seconds between
    7·1 answer
  • What order shows decreasing wavelength
    7·1 answer
  • You are in a train traveling on a horizontal track and notice that a piece of luggage starts to slide directly toward the front
    7·1 answer
  • Can you change how much power you use while exercising?
    14·1 answer
  • An artificial satellite orbits Earth at a speed of 7800 m/s and a height of 200 km above Earth’s surface. The satellite experien
    7·1 answer
  • Which of the following is NOT a characteristic of vibrations?
    7·2 answers
  • A train is rounding a circular curve whose radius is 2.55 x 102 m. At one instant, the train has an angular acceleration of 1.48
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!