Answer: Sn + 2Ag⁺ → Sn²⁺ + 2 Ag
Explanation:
1) The half-reactions given are:
Sn → Sn²⁺
Ag⁺ → Ag
2) The first step that you should perform is to complete each half reaction with electrons to balance the charges. This is how:
Sn → Sn²⁺ + 2e⁻
Ag⁺ + 1e⁻ → Ag
3) The second step is to multiply the half-reactions by the appropiate coefficients to make the electrons on both reactions equal.
So, multiply the second reaction by 2:
Sn → Sn²⁺ + 2e⁻
2Ag⁺ + 2e⁻ → 2Ag
4) The third step is to add up the two equations:
Sn + 2Ag⁺ + 2e⁻ → Sn²⁺ + 2e⁻ + 2 Ag
5) Fourth step, cancell the electrons on both sides:
Sn + 2Ag⁺ → Sn²⁺ + 2 Ag
And that is the final answer.