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AveGali [126]
3 years ago
13

Help me, ANSWER ALL 6 QUESTION, if you completed, you will have 30 POINTS

Chemistry
1 answer:
kondaur [170]3 years ago
5 0

Answer:

ONE: spoon/ catapult

TWO: ball holder

THREE: the joint

FOUR: the rotater

FIVE: I think it is a lever that picks up the big spoon/ catapult

SIX: I don't know the chapter

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In a titration experiment, how many moles of naoh will be required to completely neutralize 1 mole of nitric acid?
katrin [286]

Answer:

One mole

Explanation:

The balanced chemical equation is

<u>1</u>NaOH + <u>1</u>HNO₃ ⟶ NaNO₃ + H₂O

<u>1</u> mol       <u>1</u> mol

The coefficients in front of the formulas tell you the amount of something that reacts with an equivalent amount of something else.

In this reaction, 1 mol NaOH reacts with 1 mol HNO₃.

4 0
4 years ago
Read 2 more answers
a heliox tank contains 32% helium and 68% oxygen. the total pressure in the tank is 395 kPa. What is the partial pressure of oxy
trapecia [35]

Answer:

Pp O2 = 82.944 KPa

Explanation:

heliox tank:

∴ %wt He = 32%

∴ %wt O2 = 68%

∴ Pt = 395 KPa

⇒ Pp O2 = ?

assuming a mix of ideal gases at the temperature and volumen of the mix:

∴ Pi = RTni/V

∴ Pt = RTnt/V

⇒ Pi/Pt = ni/nt = Xi

⇒ Pi = (Xi)*(Pt)

∴ Xi: molar fraction (ni/nt)

⇒ 0.68 = mass O2/mass mix

assuming mass mix = 100 g

⇒ mass O2 = 68 g

∴ molar mass O2 = 32 g/mol

⇒ moles O2 = (68 g)(mol/32 g) = 2.125 mol O2

⇒ mass He = 32 g

∴ molar mass He = 4.0026 g/mol

⇒ moles He = (32 g)(mol/4.0026 g) = 7.995 mol He

⇒ nt = nO2 + nHe = 2.125 mol + 7.995 mol = 10.12 moles

molar fraction O2:

⇒ X O2 = nO2/nt = (2.125 mol/10.12 mol) = 0.2099

⇒ Pp O2 = (X O2)(Pt)

⇒ Pp O2 = (0.2099)(395 KPa)

⇒ Pp O2 = 82.944 KPa

6 0
3 years ago
Based on the reading, what can you infer about
Mama L [17]

Answer:

it makes the compound more digestable

Explanation:

7 0
3 years ago
Read 2 more answers
A particle with charge +1 nC (a nanocoulomb is 1 10-9 C) is located at the origin. What is the electric field due to this partic
Zolol [24]

Answer:

E=35.97\frac{V}{m}

Explanation:

The electric field of a point charge can be calculated using the next equation:

E=\frac{1}{4\pi \epsilon_0} \frac{Q}{r^2}

Where:

\epsilon_0=Absolute\hspace{3}permittivity\hspace{3}of\hspace{3}free\hspace{3}space\approx 8.85\times 10^{-12} \\Q=Charge\hspace{3}magnitude\\r=Distance

The distance can be calculated as:

r=\sqrt{0.5^2+0^2+0^2} =0.5

Using the data provided by the problem:

E=\frac{1}{4\pi (8.85\times 10^{-12}) } \frac{1\times 10^{-9} }{0.5^2} =35.96721878\approx35.97V/m

8 0
4 years ago
As the atomic numbers of the elements in column IIA increase, the size of the atoms generally
joja [24]

Answer:

Increase

Explanation:

7 0
4 years ago
Read 2 more answers
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