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UkoKoshka [18]
2 years ago
12

Students place the end of a wooden board on some books so that the board can be used as an inclined plane. The

Physics
1 answer:
snow_lady [41]2 years ago
3 0

Friction is the force that opposes motion.

<h3>What is friction?</h3>

The term friction refers to the force that hinders the movement of a surface over another. The frictional force depends on the nature of the surfaces in contact.

1) The two forces acting on the ball during the frictional force are the forward force and the frictional force.

2) The ball takes more time to roll down the incline in the presence of the cloth because of the increase in friction of the surface.

3) The students repeated the investigation there times in order to ensure accuracy of the results.

4) The energy of the ball changes from potential energy at the top of the ramp to kinetic energy as it rolls down the ramp.

Learn more about frictional force: brainly.com/question/1714663

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Use the formular d = v x t
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Which statements accurately describe mechanical waves​
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Explanation:

so a mechanical wave transfers energy through a medium but unlike other waves that move through very long distances

the distance of the mechanical wave is different

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Which interaction of nature depends on the distance through which it acts and is involved in beta decay? a. strong c. electromag
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The answer is weak.  The interaction of nature that will depend on the distance through the way it acts and involved in beta decay is the weak interaction or the weak force. This interaction is the responsible for radioactive decay which also plays a significant role in nuclear fission.

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3 years ago
5. What type of chemical reaction is shown?
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double Replacement

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7 0
2 years ago
A single Oreo cookie provides 53 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without accelerat
Sever21 [200]

Answer:

Approximately 325 (rounded down,) assuming that g = 9.81\; {\rm N \cdot kg^{-1}}.

The number of repetitions would increase if efficiency increases.

Explanation:

Ensure that all quantities involved are in standard units:

Energy from the cookie (should be in joules, {\rm J}):

\begin{aligned} & 53\; {\rm kCal} \times \frac{1\; {\rm kJ}}{4.184\; {\rm kCal}} \times \frac{1000\; {\rm J}}{1\; {\rm kJ}} \approx 2.551 \times 10^{5}\; {\rm J} \end{aligned}.

Height of the weight (should be in meters, {\rm m}):

\begin{aligned} h &= 2\; {\rm dm} \times \frac{1\; {\rm m}}{10\; {\rm dm}} = 0.2\; {\rm m}\end{aligned}.

Energy required to lift the weight by \Delta h = 0.2\; {\rm m} without acceleration:

\begin{aligned} W &= m\, g\, \Delta h \\ &= 100\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 0.2\; {\rm m} \\ &= 196\; {\rm N \cdot m} \\ &= 196\; {\rm J} \end{aligned}.

At an efficiency of 0.25, the actual amount of energy required to raise this weight to that height would be:

\begin{aligned} \text{Energy Input} &= \frac{\text{Useful Work Output}}{\text{Efficiency}} \\ &= \frac{196\; {\rm J}}{0.25} \\ &=784\; {\rm J}\end{aligned}.

Divide 2.551 \times 10^{5}\; {\rm J} by 784\; {\rm J} to find the number of times this weight could be lifted up within that energy budget:

\begin{aligned} \frac{2.551 \times 10^{5}\; {\rm J}}{784\; {\rm J}} &\approx 325 \end{aligned}.

Increasing the efficiency (the denominator) would reduce the amount of energy input required to achieve the same amount of useful work. Thus, the same energy budget would allow this weight to be lifted up for more times.

4 0
2 years ago
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