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2 years ago

Students place the end of a wooden board on some books so that the board can be used as an inclined plane. The

Physics

1 answer:

snow_lady [41]2 years ago

3 0

Friction is the force that opposes motion.

<h3>What is friction?</h3>

The term friction refers to the force that hinders the movement of a surface over another. The frictional force depends on the nature of the surfaces in contact.

1) The two forces acting on the ball during the frictional force are the forward force and the frictional force.

2) The ball takes more time to roll down the incline in the presence of the cloth because of the increase in friction of the surface.

3) The students repeated the investigation there times in order to ensure accuracy of the results.

4) The energy of the ball changes from potential energy at the top of the ramp to kinetic energy as it rolls down the ramp.

Learn more about frictional force: brainly.com/question/1714663

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An increase of 50 dB increases the sound intensity by a factor of

Artemon [7]

A factor of 50dB = a factor of 10^(50/10) = 10^5 = a factor of <em>100,000</em> .

5 0

4 years ago

A box slides down a frictionless incline, gaining speed. The work done by the normal force n is _______.

jeka57 [31]

The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

<h3>What is normal force?</h3>

The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.

This force is applied by the solid bodies on each other in order to prevent the passing through each other.

A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.

The body is gaining the speed, which means there is a change in kinetic energy.
The change in kinetic energy is equal to the work done.
The friction force is the product of coefficient of the friction and normal force.
The friction force for the given case is zero. Thus, the normal force must be equal to the zero.

Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

Learn more about the normal force here;

brainly.com/question/10941832

7 0

2 years ago

Read 2 more answers

H e l p <br> P l e a s e.

gtnhenbr [62]

Answer:

I still cant see no matter how much I zoom in!???!

Explanation:

To Small

8 0

3 years ago

Read 2 more answers

An incandescent bulb is supplied with

Serga [27]

Answer:

Efficiency = 5%

Explanation:

Given that,

Supplies energy to the bulb = 100 J

Transferred energy by the bulb = 5 J

We need to find the efficiency of the bulb. It can be given by "

$\eta=\dfrac{\text{useful energy out}}{\text{useful energy in}}\times 100\\\\=\dfrac{5}{100}\times 100\\\\=5\%$

So, the efficiency of the bulb is 5%.

8 0

3 years ago

A solid conducting sphere with radius RR that carries positive charge QQ is concentric with a very thin insulating shell of radi

svetlana [45]

Answer:

$E=0$ at r < R;

$E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}}$ at 2R > r > R;

$E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}}$ at r >= 2R

Explanation:

Since we have a spherically symmetric system of charged bodies, the best approach is to use Guass' Theorem which is given by,

$\int {E} \, dA=\frac{Q_{enclosed}}{\epsilon}$ (integral over a closed surface)

where,

$E$ = Electric field

$Q_{enclosed}$ = charged enclosed within the closed surface

$\epsilon$ = permittivity of free space

Now, looking at the system we can say that a sphere(concentric with the conducting and non-conducting spheres) would be the best choice of a Gaussian surface. Let the radius of the sphere be r .

at r < R,

$Q_{enclosed}$ = 0 and hence $E$ = 0 (since the sphere is conducting, all the charges get repelled towards the surface)

at 2R > r > R,

$Q_{enclosed}$ = Q,

therefore,

$E\times4\pi r^{2}=\frac{Q_{enclosed}}{\epsilon}$

(Since the system is spherically symmetric, E is constant at any given r and so we have taken it out of the integral. Also, the surface integral of a sphere gives us the area of a sphere which is equal to $4\pi r^{2}$ )

or, $E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}}$

at r >= 2R

$Q_{enclosed}$ = 2Q

Hence, by similar calculations, we get,

$E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}}$

4 0

4 years ago