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AleksandrR [38]
3 years ago
15

What occurs when a solid substance dissolves into a liquid? 1 It stays solid and sinks to the bottom of the liquid substance. 2

It breaks down and becomes part of the liquid substance. 3 It stays solid and floats on the top of the liquid substance. 4 It changes the liquid substance into a solid substance.
Chemistry
1 answer:
katrin [286]3 years ago
6 0

Explanation:

When a solid substance is dissolved in a liquid such as water, the intermolecular forces of attraction between the molecules in the solid substance are overcome and they exist as ions in the solution. Hence the answer is 2.

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If you leave a glass of water and ice on the kitchen counter long enough, after a while you will have just a glass of water. why
irakobra [83]
The heat of the water is shared with the ice and there for you drink will get cold but your ice will melt away from the heat going in the ice
8 0
3 years ago
If 35.50 cm3 of a NaOH solution are required for the complete neutralization of a 25.00cm3 sample of 0.200mol dm-3 H2SO4, what i
Morgarella [4.7K]
In this question, you are given the NaOH volume but asked for concentration. 
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:

OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
6 0
3 years ago
To calculate the Ksp of 0.34 g of cesium sulfate (Cs2SO4) in 1.00 L of aqueous solution, which equilibrium equation will you use
FinnZ [79.3K]

Answer:C

Explanation:

5 0
3 years ago
How many grams S03<br> are needed to make 400g<br> H₂So4 in 49%
NemiM [27]

160 g of SO3 are needed to make 400 g of 49% H2SO4.

<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>

The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}

1 mole of SO3 produces 1 mole of H2SO4

Molar mass of SO3 = 80 g/mol

Molar mass of H2SO4 = 98 g/mol

80 g of SO3 are required to produce 98 og 100%H2SO4

mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3

Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g

Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.

Learn more about mass and moles at: brainly.com/question/15374113

#SPJ1

7 0
2 years ago
What is the mass of 4.5 moles of Cu(NO3)2?
Tatiana [17]

Answer:

The mass of 4.5 moles of Cu(NO3)2 is 843.55g

Explanation:

Mass = moles x Molar mass

Mass = 4.50(187.55)

         = 843.97g

6 0
3 years ago
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