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3 years ago

How does the location of hydrogen on the periodic table differ from the locations of other nonmetals?

1 answer:

4 0

It's special, because it has only one electron, while the ideal "noble gas" configuration (helium) would call for two.

EXPLANATION:

So in one way it could 'try' to gain an electron as any element from halogen group (F-Cl-Br...) would do.
On the other hand it could lose its one electron, in which case it would belong to the alkali metals (Li-Na-K...).

In practice, H mostly shares its electron, either by covalent bonds, or by donating an electron and working together with H2O to form the H3O+or 'acid' ion.

In short, H is too special to to put it in a specific Group.

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Standard reduction potentials are based on which element?

KonstantinChe [14]

They're based on hydrogen.

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3 years ago

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Determine the percentage of carbon and hydrogen in ethane C2H6 if the molecular weight is 30.

Naddika [18.5K]

Answer:

Percentage of carbon:

${ \tt{ = \frac{24}{30} \times 100\%}} \\ = 80\%$

Percentage of hydrogen:

${ \tt{ = \frac{6}{30} \times 100\%} } \\ = 20\%$

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3 years ago

How many atoms of hydrogen are present in 7.63 g of ammonia? please help me ??

GarryVolchara [31]

The atoms of hydrogen that are present in 7.63 g of ammonia(NH3)

find the moles of NH3 =mass/molar mass
7.63 g/ 17 g/mol = 0.449 moles

since there is 3 atoms of H in NH3 the moles of H = 0.449 x 3 = 1.347 moles

by use of 1 mole = 6.02 x10^23 atoms
what about 1.347 moles

= 1.347 moles/1 moles x 6.02 x10^23 atoms = 8.11 x10^23 atoms of Hydrogen

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3 years ago

The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release

KATRIN_1 [288]

The mass of melted gold to release the energy would be 3, 688. 8 Kg

<h3>How to determine the mass</h3>

The formula for quantity of energy is given thus;

Q = n × HF

Where n represents number of moles

HF represents heat of fusion

To find the number of moles, we have

235.0 = n × 12.550

number of moles = $\frac{235}{12. 550}$ = 18. 725 moles

Note that molar mass of Gold is 197g/ mol

Let's note that;

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Mass = 18. 725 × 197

Mass = 3, 688. 8 Kg

Thus, the mass of melted gold to release the energy would be 3, 688. 8 Kg

Learn more about molar heat of fusion here:

brainly.com/question/15634085

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1 year ago

Gas particles do not have much energy of motion.<br><br> True or False?

QveST [7]

False is the answer

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3 years ago

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