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andre [41]
3 years ago
12

How does the location of hydrogen on the periodic table differ from the locations of other nonmetals?

Chemistry
1 answer:
Tom [10]3 years ago
4 0
It's special, because it has only one electron, while the ideal "noble gas" configuration (helium) would call for two.

EXPLANATION:

So in one way it could 'try' to gain an electron as any element from halogen group (F-Cl-Br...) would do.
On the other hand it could lose its one electron, in which case it would belong to the alkali metals (Li-Na-K...).

In practice, H mostly shares its electron, either by covalent bonds, or by donating an electron and working together with H2O to form the H3O+or 'acid' ion.

In short, H is too special to to put it in a specific Group.

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Can some help me please?
Tom [10]

Answer:

159.7 g Fe2o3/1 mol Fe2o3

3 0
3 years ago
Group 1 elements have an average electronegativity of 0.84 (not
sergey [27]

A) The bond that will be formed by these elements is : <u>Ionic Bond </u>

B) Group 1 elements Gives up its electron to Group 17 elements

<h3><u /></h3><h3><u>Electronegativity values </u></h3>

From the electronegativity values given in the question group 17 elements with an electronegativity value of 2.99 are more electronegative than group 1 elements with a value of 0.84. Therefore they accept electron transfer from group 1 elements.

The acceptance of electrons from group 17 elements leads to formation of an ionic bond between group 1 and group 17.

Hence we can conclude that the bond that will be formed by these elements is Ionic bond  and Group 1 elements gives up its electron to group 17 elements.

Learn more about Ionic bonds : brainly.com/question/13526463

7 0
2 years ago
Who knows this........​
kvv77 [185]

Answer:

D

Explanation:

This creates a gap that we call an oceanic trench

:)

4 0
2 years ago
Read 2 more answers
Find the boiling point temperature at 760 torr of an isomer of octane, c8h18, if its enthalpy of vaporization is 38,210 j mol-1
mixas84 [53]

According to Clausius-Clayperon equation,

ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} }   )

P_{1}is the vapor pressure at boiling point = 760 torr

P_{2} is the vapor pressure at T_{2} =638.43 torr

TemperatureT_{2} = 110.0^{0}C + 273 = 383 K

ΔH_{vap} = 38210 J/mol

Plugging in the values, we get

ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} }   )

ln\frac{760 torr}{638.43 torr} =\frac{38210 J/mol}{8.314 J/(mol.K)} (\frac{1}{383 K}-\frac{1}{T_{1} }

T_{1} = 389 K

Therefore, the boiling point of octane = 389 K - 273 = 116^{0}C

7 0
3 years ago
Which of the following describe a neutron?
dalvyx [7]
Neutron is subatomic particel with with mass approximately one atomic mass unit, and neutron mass slightly larger than proton.
neutron have natural charge and i suppose that the mass may be called as: a. mass number of 1.

hope this help
6 0
4 years ago
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