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Mkey [24]
2 years ago
7

Bài 1: Đốt cháy 28 lít khí mêtan CH4 trong không khí sinh ra khí cacbon đioxit và hơi nước.

Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
7 0

Answer:

gghdxfjnj8jh7fwft

Explanation:

ffujggvggggfffffffrrrd

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How many moles of a solute is contained in 500mL of a 2.5 M solution?
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How many grams of NaF form when .5 mol of HF reacts with excess Na2SiO3?
IgorLugansk [536]

Answer:

5.25g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is shown below:

Na2SiO3 + 8HF → H2SiF6 + 2NaF + 3H2O

From the balanced equation above,

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Therefore, 0.5 moles of HF will react to produce = (0.5 x 2)/8 = 0.125 mole of NaF.

Next, we shall convert 0.125 mole of NaF to grams.

This is illustrated below:

Mole of NaF = 0.125 mole

Molar mass of NaF = 23 + 19 = 42g/mol

Mass of NaF =..?

Mass = mole x molar mass

Mass of NaF = 0.125 x 42

Mass of NaF = 5.25g

Therefore, 5.25g of NaF is produced from the reaction.

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