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4vir4ik [10]
3 years ago
7

A 3.00-kg mass rests on the ground. It is attached to a string which goes vertically to and over an ideal pulley. A second mass

is attached to the other end of the string and released. The 3.00-kg mass rises 50.0 cm in 1.00 s. How large was the other mass?
A) 3.67 kg
B) 4.29 kg
C) 6.83 kg
D) 7.15 kg
E) 7.34 kg
Physics
1 answer:
s344n2d4d5 [400]3 years ago
8 0

Answer:A

Explanation:

mass of object=3 kg

distance moved=50 cm

time t=1 s

s=ut+\frac{at^2}{2}

0.5=0+\frac{a\cdot 1^2}{2}

a=1 m/s^2

Let T is the tension in rope

T-mg=ma

Let M be the other mass

Mg-T=Ma

T=M(g-a)

M=m\frac{g+a}{g-a}

M=3\times \frac{9.8+1}{9.8-1}

M=3\times 1.227

M=3.67 kg

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