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Arte-miy333 [17]
3 years ago
10

Find the acceleration of a car with the mass of 1,200 kg and a force of

Physics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:9.17 m/s^2

Explanation:

mass=1200kg

Force=11 x 10^3 N

Acceleration=force ➗ mass

Acceleration=11 x 10^3 ➗ 1200

Acceleration=9.17

Acceleration=9.17 m/s^2

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4.) 3rd law of motion.
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5.) 1st law of motion.
6 0
3 years ago
The tendency to perceive a series of points or lines as having unity is the Gestalt rule of organization known as ________.
xxMikexx [17]
The best answer to fill in the blank should be ''continuation'' because series means a lot and lines are long, narrow, figures, so its continuation since its constant.
5 0
3 years ago
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Auroras occur at _____ of a planet. the equator the north magnetic pole only the south magnetic pole only both magnetic poles
goldenfox [79]

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3 0
3 years ago
Two forces act on wooden box with mass of (30kg) (if F1,=85.7N east and F270.7N west):
tresset_1 [31]

The acceleration of the wooden box is 6.17 m/s² towards the west.

<h3 /><h3>What is acceleration?</h3>

Acceleration can be defined as the rate of change of velocity.

To calculate the acceleration of the wooden box can be calculated using the formula below.

Formula:

  • F₂-F₁ = ma.................. Equation 1

Where:

  • F₂ = Force on the wooden box acting towards west
  • F₁ = Force on the wooden box acting towards the east
  • m = Mass of the wooden box.
  • a = Acceleration of the wooden box

Make a the subject of the equation

  • a = (F₂-F₁)/m........................ Equation 2

From the question,

Given:

  • F₂ = 270.7 N
  • F₁ = 85.7 N
  • m = 30 kg

Substitute these values into equation 2

  • a = (270.7-85.7)/30
  • a = 185/30
  • a = 6.17 m/s² towards the west.

Hence, The acceleration of the wooden box is 6.17 m/s² towards the west.

Learn more about acceleration here: brainly.com/question/605631


7 0
2 years ago
Consider the equation . The dimensions of the variables v, x, and t are , , and , respectively. The numerical factor 3 is dimens
Vinvika [58]

Answer:

Part of the question is missing but here is the equation for the function;

Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.

Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3

Explanation:

What is applied is the principle of dimensional homogenuity

From the equation V = (1/3)zxt2.

  • V has  a dimension of [L/T]
  • x has a dimension of [L]
  • t has a dimension of [T]
  • from the equation, make z the subject of the relation
  • z = v/xt2 where 1/3 is treated as a constant
  • Substituting into the equation for z
  • z = L/T / L x T2
  • the dimension for z = 1/T3 i.e 1/ T - raised to power 3
5 0
3 years ago
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