Answer: When an inert gas is added to the system in equilibrium at constant pressure, then the total volume will increase.
Explanation:
Answer:
A ,B- false
C,D- true
Explanation:
Dipole forces always lead to stronger attraction and boiling points than dispersion forces. When linear molecules are involved, they often posses greater dipole forces and higher boiling points. Linear alkanes posses higher boiling points than branched alkanes.
Answer: Yes fertilizers do make plants grow faster but the three combined water, sunlight, and fertilizer they grow much faster.
Explanation:
The given chemical reaction is:
![2Br^- (aq) + I_2(s) Br_2(l) + 2I^- (aq)](https://tex.z-dn.net/?f=2Br%5E-%20%28aq%29%20%2B%20I_2%28s%29%20%3C-%3E%20Br_2%28l%29%20%2B%202I%5E-%20%28aq%29)
![E^ocell=oxidation potential of anode + reduction potential of cathode\\](https://tex.z-dn.net/?f=E%5Eocell%3Doxidation%20potential%20of%20anode%20%2B%20reduction%20potential%20of%20cathode%5C%5C)
The relation between Eo cell and Keq is shown below:
![deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell](https://tex.z-dn.net/?f=deltaG%3D-RTlnK_e_q%5C%5Cdelta%3D-nFE%5Eo%20cell%5C%5C%3D%3EnFE%5Eo%20cell%3DRTlnK_e_q%5C%5ClnK_e_q%3D%5Cfrac%7BnF%7D%7BRT%7D%20E%5Eo%20cell)
The value of Eo cell is:
Br- undergoes oxidation and I2 undergoes reduction.
Reduction takes place at cathode.
Oxidation takes place at anode.
Hence,
![E^ocell= (-1.07+0.53)V\\=-0.54V](https://tex.z-dn.net/?f=E%5Eocell%3D%20%28-1.07%2B0.53%29V%5C%5C%3D-0.54V)
F=96485 C/mol
n=2 mol
R=8.314 J.K-1.mol-1
T=298K
Substitute all these values in the above formula:
![ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3](https://tex.z-dn.net/?f=ln%20K_e_q%3D%5Cfrac%7B2mol%2A%2096485%20C%2Fmol%7D%7B8.314%20J.K%5E-%5E1.mol%5E-%5E1x298K%7D%20%5C%5C%5C%5ClnK_e_q%3D77.8%5C%5CK_e_q%3De%5E7%5E7%5E.%5E8%5C%5C%3D%3EK_e_q%3D6.13x10%5E3%5E3)
Answer:
Keq=6.13x10^33
From what I would think, it is D.