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marissa [1.9K]
3 years ago
11

Hormone progestone is secreted by which gloads​

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
3 0
Horme protestin by 3;4
You might be interested in
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points from highest to l
muminat

Answer:

NH4Cl > Li2SO4 > CoCl3

Explanation:

Let us recall that the freezing point depression depends on the molality of the solution and the number of particles present.

Let us also recall that freezing point depression is a colligative property. It depends on the number of particles present in solution.

Usually, the more the number of particles present, the lower the freezing point. Hence, NH4Cl which has only two particles will have the highest freezing point while CoCl3 which has four particles will have the lowest freezing point.

4 0
3 years ago
Can you substitute evaporated milk for condensed milk
alex41 [277]
Yes because condensed milk and evaporated milk are similar to one another. However, there won’t be the same sweet flavor but the texture is the same.
3 0
3 years ago
Calculate the maximum concentration (in m) of silver ions (ag+) in a solution that contains 0.025 m of co32-. the ksp of ag2co3
Helen [10]
Equilibrium equation is

<span>Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) </span>

<span>From the reaction equation above, the formula for Ksp: </span>

<span>Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 </span>
<span>You know  [CO32-], so you can solve for [Ag+] as: </span>
<span>(8.1 x 10^-12) = [Ag+]^2 (0.025) </span>
<span>[Ag+]^2 = 3.24 x 10^-10 </span>
<span>[Ag+] = 1.8 x 10^-5 M </span>
5 0
4 years ago
Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer t
nekit [7.7K]

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

n = \frac{m}{M}

<u>Where:</u>

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

n = \frac{m}{M} = \frac{14 g}{56.1056 g/mol} = 0.249 mol

The enthalpy change is:

\Delta H = -43 \frac{kJ}{mol}*0.249 mol = -10.71 kJ

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

5 0
3 years ago
a 15.0 L tank of gas is contained at a high pressure of 8.20*10^4. The tank is opened and the gas expands into an empty chamber
Nostrana [21]

Answer:

P_2=20.5

Explanation:

Assuming that temperature is constant

According to Boyle's Law, at constant temperature pressure is inversly proportional to the volume  and mathematically it can be expressed as:

P_1V_1 = P_2V_2..........1

P_1=8.2 \times 10^4

P_2=?

V_1=15L

V_2=6.00 \times 10^4L

from the first equation after putting all the value

we get,

P_2=20.5

8 0
3 years ago
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