It’s Florine! And the formula is F subscript 2
Answer:
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
Explanation:
Taking natural logarithm on both the sides:
Slope intercept form is generally given as:
m = slope, c = intercept on y axis or vertical axis
On rearranging equation:
y = ln [(y+3)], x = ln [(x-2)], m=-1 , c = ln 2b
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
Answer:
A) <u><em>Dinitrogen Oxide:</em></u>
=> (Also called Nitrous Oxide)
B) <u><em>Calcium Dihydrogen Phosphate:</em></u>
=> (Also called Monocalcium phosphate)
Answer:
2,500,000 litres or 2.5 megalitres of water.
Olympic size pools measure: 50 metres long, 25 metres wide, and a minimum of 2
metres deep.
(25m x 50m x 2m = 2,500m3; 1L = 0.001m3 so 2,500 x 1000 = 2,500,000L)
660,430 gallons of water.
50 meters = 164.041995 feet (a)
25 meters = 82.0209975 feet (b)
2 meters = 6.5616798 feet (c)
Volume = (a) * (b) * (c) = 88,286.66721 cubic feet Explanation:
A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by ventilation.
The two following principles determine the type of ventilation: Considering the impact of the contaminant's vapour density and either positive or negative pressure is applied.
Consider a vertical tank that is filled with methane gas. Methane would leak out if we opened the top hatch since its vapour density is far lower than that of air. A second opening could be built at the bottom to greatly increase the process' efficiency.
A faster atmospheric turnover would follow from air being pulled in via the bottom while the methane was vented out the top. The rate of natural ventilation will increase with the difference in vapour density. Numerous gases that require ventilation are either present in fairly low concentrations or have vapor densities close to one.