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denpristay [2]
3 years ago
6

Consider the atom with the chemical symbol Ru.

Chemistry
1 answer:
babymother [125]3 years ago
7 0

Answer:

96.

Explanation:

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A alkaline earth metal is an element is groups 3-12 of the periodic table true or false?
Karo-lina-s [1.5K]

False Alkaline earth metals is group 2

5 0
3 years ago
In which layer(s) would a solid cube with 6 cm sides and mass of 270 g float? Explain.
DIA [1.3K]
The buoyancy of an object is dictated by its density. So let us calculate for density, where:density = mass / volume
Calculate the volume first of a solid cube:volume = (6 cm)^3 = 216 cm^3 = 216 mL
Therefore density is:density = 270 g / 216 mLdensity = 1.25 g / mL
Therefore this object will float in the layer in which the density is more than 1.25 g / mL.
6 0
3 years ago
What is the molarity (molar concentration, unit = M) of K+ found in 200 mL 0.2 M K2HPO4 solution?
enyata [817]

Answer:

0.4 M

Explanation:

The process that takes place in an aqueous K₂HPO₄ solution is:

  • K₂HPO₄ → 2K⁺ + HPO₄⁻²

First we <u>calculate how many K₂HPO₄ moles are there in 200 mL of a 0.2 M solution</u>:

  • 200 mL * 0.2 M = 40 mmol K₂HPO₄

Then we <u>convert K₂HPO₄ moles into K⁺ moles</u>, using the <em>stoichiometric coefficients</em> of the reaction above:

  • 40 mmol K₂HPO₄ * \frac{2mmolK^+}{1mmolK_2HPO_4} = 80 mmol K⁺

Finally we <em>divide the number of K⁺ moles by the volume</em>, to <u>calculate the molarity</u>:

  • 80 mmol K⁺ / 200 mL = 0.4 M
5 0
3 years ago
What is the mole ratio of  to Fe?<br><br>1:3<br><br>1:4<br><br>3:1<br><br>4:3
kobusy [5.1K]

What is the mole ratio of  to Fe? if oxygen it is 4:3  Fe3O4

8 0
3 years ago
QUESTION 7
Temka [501]

The student's test average is : 0.92

Total score obtained = 369

Number of tests = 4

Since Each test is exactly 100 points ;

The total score obtainable is (100 × 4) = 400

Average = score obtained / total score obtainable

Average = 369 / 400

Average = 0.9225

Average = 0.92

Learn more : brainly.com/question/9416487?referrer=searchResults

5 0
3 years ago
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