Answer:
Step-by-step explanation:
![\sf \sqrt{-10} \\\\\sqrt{10} * \sqrt{-1} \\\\We \ know \ that \ \sqrt{-1} = i\\\\= \sqrt{10} i\\\\= \sqrt{2*5 } i \\\\Since \ 2 \ and \ 5 \ are \ not \ perfect \ squares, they \ cannot \ be \ simplified\ further.\\\\= \sqrt{10} i\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B-10%7D%20%5C%5C%5C%5C%5Csqrt%7B10%7D%20%2A%20%5Csqrt%7B-1%7D%20%5C%5C%5C%5CWe%20%5C%20know%20%5C%20that%20%5C%20%5Csqrt%7B-1%7D%20%3D%20i%5C%5C%5C%5C%3D%20%5Csqrt%7B10%7D%20i%5C%5C%5C%5C%3D%20%5Csqrt%7B2%2A5%20%7D%20i%20%5C%5C%5C%5CSince%20%5C%202%20%5C%20and%20%5C%205%20%5C%20are%20%5C%20not%20%5C%20perfect%20%5C%20squares%2C%20they%20%5C%20cannot%20%5C%20be%20%20%5C%20simplified%5C%20further.%5C%5C%5C%5C%3D%20%5Csqrt%7B10%7D%20i%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Step-by-step explanation:
here you go mate'
step 1
(60 + 10)130 equation
step 2
(60 + 10)130 simplify with the brackets
step 3
130(70) multiply the numbers
answer
9100
Let's solve your system by substitution.
3x−2y=−12;4x+5y=7
Step: Solve3x−2y=−12for x:
3x−2y=−12
3x−2y+2y=−12+2y(Add 2y to both sides)
<u>3x</u>= <u>2y−12
</u>
3 3
=
<u>2y−12
</u>
3
(Divide both sides by 3)
x=
<u>2
</u>
3 y−4
Step: Substitute
<u>2
</u>
3
y−4 for x in 4x+5y=7:
4x+5y=7
4(
2/3 y−4)+5y=7
<u>23
</u>
3
y−16=7(Simplify both sides of the equation)
<u>23</u>
3
y−16+16=7+16(Add 16 to both sides)
<u>23</u>
3
y=23
<u>23</u>
3 y
<u>23
</u>
3 = 23<u>
</u>
<u>23
</u>
3
(Divide both sides by 23/3)
y=3
Step: Substitute 3 for y in x=
<u> 2 </u>
3
y−4:
x=
<u> 2 </u>
3
y−4
x= <u> 2 </u>
3
(3)−4
x=−2(Simplify both sides of the equation)
Answer:
x=−2 and y=3 (underlined and / are fractions or division)
Answer:
x=0
Step-by-step explanation:
-8x + 2(4x + 2) = 4
Use distributive property to get rid of the parentheses
-8x + 8x + 4 = 4
Add the like terms.
x + 4 = 4
Subtract both sides by four.
x = 0
Answer:
8
Step-by-step explanation:
