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Free_Kalibri [48]
3 years ago
9

On level ground a shell is fired with an initial velocity of 46.0 m/s at 66.0 ∘ above the horizontal and feels no appreciable ai

r resistance.
Physics
1 answer:
olga_2 [115]3 years ago
8 0
Initial velocity v = 86.6 m / s
angle ,theta = 63.7 degrees
(A). the horizontal component of the shell's initial velocity = v cos 63.7 = 38.36 m / s
vertical component of shells' initial velocity = v sin 63.7 = 77.63 m / s
(B). time taken to reach maximu height t = v sin (theta ) / g
= 7.922 s
(C). Maximum height H = ( v sin(theta) )^ 2/ 2g
= 307.5 m
(D). Required distance = v^ 2 *sin2(theta) / g
= 607.9 m
(E). Horizontal component of accleraton = 0
vertical component of accleration = g = 9.8 m / s^ 2
(F). horizontal component of velocity at required point = v cos (theta ) = 38.36 m / s
vertical compoent of velocity at required point = 0
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Answer:

18m

Explanation:

v=frequency × wavelenght

wavelength=v/f

wavelength=360÷20

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7 0
3 years ago
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Describe some precautions needed to increase the safety of participants in the sports of football.
OLga [1]
Football is a popular ball game and so many people play football these days. Been a contact game, there is no way players will not sustain injuries, but this can be reduced to the lowest point by taking some precautions.
The precautions that could be taken include the following:
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8 0
3 years ago
The octopus’s tentacle keeps _ right after it is bitten off ? a. Moving b. Breathing c. Growing
konstantin123 [22]

Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off

5 0
2 years ago
A 12.0 kg object is attached to a cord that is wrapped around a wheel of radius 10.0 cm. the acceleration of the object down the
olganol [36]

 a) We use the formula:

T = [g sinθ – a] * m

where g is gravity, θ is the angle, a is acceleration, m is mass

T = [9.81 sin37 - 2.00] * 12 = 46.85 N <span>

b) We use the formula for moment of interia:</span>

I = T * r² / a

I = 46.85 * 0.10² / 2.00 = .2343 kg∙m² <span>

c) The formula we can use here is:</span>

w = α * t = (a/r) * t

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6 0
3 years ago
The coefficient of static friction between car's tires and a level road is 0.80 If car to be stopped in time of 3.0 sec its spee
Vlad1618 [11]

Answer:

23.5 m/s

Explanation:

The velocity of the car in decelerated motion is given by

v = u + at

where

v = 0 is the final velocity

u is the initial velocity

a is the acceleration of the car

t = 3.0 s is the time it takes for the car to stop

The acceleration of the car is given by the frictional force, which is the only force acting on the car along the direction of motion, so:

ma = -\mu mg\\a = -\mu g = -(0.80)(9.8 m/s^2)=-7.84 m/s^2

where

\mu=0.80 is the coefficient of friction

Solving the previous equation for u, we find the initial velocity:

u=v-at=0-(-7.84 m/s^2)(3.0 s)=23.5 m/s

4 0
4 years ago
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