Answer:
1.2 x 10¹¹ kgm²/s
Explanation:
m = mass of the airplane = 39043.01
r = altitude of the airplane = 9.2 km = 9.2 x 1000 m = 9200 m
v = speed of airplane = 335 m/s
L = Angular momentum of airplane
Angular momentum of airplane is given as
L = m v r
Inserting the values
L = (39043.01 ) (335) (9200)
L = (39043.01 ) (3082000)
L = 1.2 x 10¹¹ kgm²/s
Answer:
The speed of the crate is 0.52m/S
Explanation:
Hello!
The first step to solve this problem is to find the necessary torque to raise the load, for this we use the following equation
T=mgr
m=mass=1500kg
t=torque
g=gravity=9.81m/s^2
r=radius=180mm=0.18m
T=(1500)(0.18)(9.81)=2648.7Nm
the second step is to find the torque on the motor side using the reduction ratio for this we divide the torque found by 60
The third step is to find the turning speed with the torque speed equation and solving the quadratic equation
T=
The fourth step is to solve the quadratic equation which results in N =1656.6RPM(remember take the positive solution)
the fifth step is to find the speed of rotation at the output of the speed reducer for this we divide by 60
finally to find the speed of the box remember that it is the product of the speed of rotation in Rad / s by the radius in m
V=
The speed of the crate is 0.52m/S
The mass that cannot be found inside the nucleus
Answer:
Explanation:
For this problem we have to find the formula for acceleration.
F = ma
So since we already know force and looking for acceleration, we have to change it up a bit.
A = F / m
The force is 3000-N
A = 3000/ m
The mass is 200-kg
A = 3000/ 200
Do the division:
3000/ 200
15
A = 15