This question does not contain the structures of the molecules. The structures in Daylight SMILES format are:
I. C1=CC=CC=C1C(=O)C
II. C1=CC=CC=C1CC=O
III. C1=CC(C)=CC=C1C=O
IV. C1=CC=CC=C1CCC
V. C1=CC=CC=C1C(C)C
The structures are also attached
Answer:
The structure of compound IV is consistent with the information obtained analysis
Proposed structures for the ions with m/z values of 120, 105,77 and 43 are (also attached):
C1=CC=CC=C1C(=[OH0+])C |^1:7|
C1C([CH0+]=O)=CC=CC=1
C1[CH0+]=CC=CC=1
C(#[OH0+])C
respectively
Explanation:
The IR peak at 1687 cm⁻¹ is indicative of an α unsaturated carbonyl carbon. While the 1H NMR singlet is of the methyl group next to carbonyl and the multiplet near 7.1 ppm is a characteristic peak of benzene. This data shows points towards structure I.
Mass spectrum peak at 120 m/z is of molecular ion peak. In the case of carbonyl-containing molecule, this peak is observable. The signal at 105 shows the loss of a methyl group next to the carbonyl. m/z value of 77 is the characteristic cationic peak of benzene, while the peak at 43 infers the formation of acylium ion (RCO+) due to α-cleavage. All this data agrees with the structure of acetophenone (Structure 1)
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The answer to your question would be as followed:
The most precise measurement for the cylinder you are mentioning is <em><u>B. 43.0mL</u></em>
The chemical formula for the compound magnesium perchlorate is Mg(ClO₄)₂
Magnesium perchlorate or Mg(ClO₄)₂ is an ionic compound.
Perchlorate here is an anion which is represented by ClO₄⁻. Perchlorate is a polyatiomic anion, where one Cl atom is bonded to four O atoms.
The magnesium cation is represented by Mg²⁺
So one Mg²⁺ cation combines with two ClO₄⁻ anion to form one molecule of Mg(ClO₄)₂

now split the equation in half
CH4+O2 I CO2 + 4H2O
C = 1 I C = 1
H = 4 I H = 8
O = 2 I O = 3
CH4+ 2O2 = CO2 + 2H20
Answer:
Mass of Ca(OH)₂ required = 0.09 g
Explanation:
Given data:
Volume of HNO₃ = 25 mL (25/1000 = 0.025 L)
Molarity of HNO₃ = 0.100 M
Mass of Ca(OH)₂ required = ?
Solution:
Chemical equation;
Ca(OH)₂ + 2HNO₃ → Ca(NO)₃ + 2H₂O
Number of moles of HNO₃:
Molarity = number of moles / volume in L
0.100 M = number of moles / 0.025 L
Number of moles = 0.100 M ×0.025 L
Number of moles = 0.0025 mol
Now we will compare the moles of Ca(OH)₂ with HNO₃ from balance chemical equation.
HNO₃ : Ca(OH)₂
2 : 1
0.0025 : 1/2×0.0025 = 0.00125
Mass of Ca(OH)₂:
Mass = number of moles × molar mass
Mass = 0.00125 mol × 74.1 g/mol
Mass = 0.09 g