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oksian1 [2.3K]
3 years ago
11

When graphing the following equation which one will give you a straight line?

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

the second one f(x)=2/3x+1

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Please help I will BRAINLIST if right
katen-ka-za [31]

Answer:

25x^{4}y²

Step-by-step explanation:

The area (A) of a square is calculated as

A = s² ( s is the side length )

A = (5x²y)²

  = 5 × 5 × x² × x² × y × y

  = 25x^{4}y²

5 0
3 years ago
The slope of the line below is 0.5. Write the equation of the line in point-slope form, using the coordinates of the labeled poi
Arturiano [62]
The complete question is
The slope of the line below is 0.5 Write the equation of the line in point-slope form, using the coordinates of the labeled point. <span>It's on a number line which is (3,-3) Do not use parenthesis on the y side.

we know that

</span>Point slope form is 
<span>y - y₁ = m(x - x₁) </span>

<span>Where m= slope and (x₁, y₁) is a point on the line 
</span><span>Plug in m = 0.5 and point (3, -3) 
</span><span>y-(-3)=0.5*(x-3)------> y+3=0.5*(x-3)

the answer is
</span> y+3=0.5*(x-3)<span>


</span>
8 0
4 years ago
Which equation represents a line that passes through (–9, –3) and has a slope of –6?
Dahasolnce [82]
<h2>Hello!</h2>

The answer is:

The last equation,

y+3=-6(x+9)

<h2>Why?</h2>

To find which of the given equations represents a line that passes through the point (-9,-3) and has a slope of -6, we need to find an equation that can be satisfied by evaluating the given point.

We can see that the only equation that can be satisfied evaluating the point (-9,-3) is the last equation:

y+3=-6(x+9)

Evaluating the point, we have:

-3+3=-6*(-9+9)

0=-6*(0)

0=0

We can see that the equation is satisfied!

Also, we can see that evaluating the point into the other equations, they will not be satisfied.

Let's prove that:

Evaluating:

First equation:

y-9=-6(x-3)\\-3-9=-6*(-9-3)\\-12=-6*(-12)=72

The equation is not satisfied.

Second equation:

y+9=-6(x+3)\\-3+9=-6*(-9+3)\\6=-6*(-6)=36

The equation is not satisfied.

Third equation:

y-3=-6(x-9)

-3-3=-6(-9-9)

-6=-6(-18)=108

The equation is not satisfied.

Hence, the correct option is the last option, the equation that represents a line that passes through (–9, –3) and has a slope of –6 is the last equation:

y+3=-6(x+9)

Have a nice day!

Note: I have attached a picture for better understanding.

5 0
3 years ago
Read 2 more answers
Arsenic is a compound that occurs naturally in very low concentrations. Arsenic blood concentrations in healthy adults are Norma
DENIUS [597]

Answer:

0.7325 to 5.6675 ug/dl

Step-by-step explanation:

The middle 90% will be 45% above the mean and 45% below the mean.  This means

0.5-0.45 = 0.05 and

0.5+0.45 = 0.95

We use a z table.  Look in the cells; find the values as close to 0.05 and 0.95 as we can get.

For 0.05, we have 0.0505 and 0.0495; since these are equidistant from 0.05, we use the value between them.  0.0505 is z=-1.64 and 0.0495 is z=1.65; this gives us z=-1.645.

For 0.95, we have 0.9495 and 0.9505; since these are equidistant from 0.95, we use the value between them.  0.9495 is z = 1.64 and 0.9505 is z=1.65; this gives us z = 1.645.

Now we use our z score formula,

z=\frac{X-\mu}{\sigma}

Our two z scores are 1.645 and -1.645; our mean, μ, is 3.2; and our standard deviation, σ, is 1.5:

1.645=\frac{X-3.2}{1.5}

Multiply both sides by 1.5:

1.5(1.645)=\frac{X-3.2}{1.5}\times 1.5\\\\2.4675 = X-3.2

Add 3.2 to each side:

2.4675+3.2 = X-3.2+3.2

5.6675 = X

-1.645=\frac{X-3.2}{1.5}

Multiply both sides by 1.5:

1.5(-1.645)=\frac{X-3.2}{1.5}\times 1.5\\\\-2.4675=X-3.2

Add 3.2 to each side:

-2.4675+3.2 = X-3.2+3.2

0.7325 = X

Our range is from 0.7325 to 5.6675.

5 0
3 years ago
За + 2b – 8а + Ь<br> Please help
hoa [83]
Combine the like terms
3b-5a
Or -5a+3b if keeping in a certain order
7 0
3 years ago
Read 2 more answers
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