The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
<h3>What is Electric field?</h3>
Electric field is the physical field that surrounds a charge.
<h3>How to find final velocity of the electron when it moves some distance in a certain electric field?</h3>
- From Newton's second law, the acceleration the electron will be
a=F/m=qE/m
- where q= charge of electron
E= electric field
m= mass of electron
=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)
=10¹⁵×0.526m/s²
- The kinematics equation v²=v0²+2a(Δx)
- where v=final velocity of the electron
v0=initial velocity of the electron =5×10⁶m/s
a=acceleration of the electron =10¹⁵×0.526m/s²
Δx=distance moved by the electron in east direction =1cm=10^-2m
- Now v^2=(5×10⁶)²+2×10¹⁵×0.526×10^-2
=25×10¹²+10.52×10¹²
=35.52×10¹²
- Now velocity of electron=5.95×10⁶m/s.
Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
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Answer:
5.1 meters
Explanation:
Terra tosses a 0.20kg volleyball up at at a speed of 10 m/s
The height can be calculated as follows
= v^2/2g
= 10^2/2×9.8
= 100/19.6
= 5.1 meters
Hence the height is 5.1 meters
It is a type capacitor is in which two metal plates arranged in such a way so that they are connected in parallel . The potential energy is stored in the capacitor will be 2.7×10⁻⁵.
<h3>What is parallel plate capacitor ?</h3>
It is an type capacitor is an in which two metal plates arranged in such a way so that they are connected in parallel and have some distance between them.
A dielectric medium is a must in between these plates. helps to stop the flow of electric current through it due to its non-conductive nature .
The given data in the problem is;
Q is the charge= 1.5 µC
V is the change in voltage across the plates is = 36 V.
U is the potential energy=?
The formula for the potential energy is given by;

Hence the potential energy is stored in the capacitor will be 2.7×10⁻⁵.
To learn more about the parallel plate capacitor refer to the link;
brainly.com/question/12883102
Answer:
v_average = (d₂-d₁) / Δt
this average velocity is not necessarily the velocity of the extreme points,
Explanation:
To resolve the debate, it must be shown that the two have part of the reason, the space or distance between the two points divided by time is the average speed between the points.
v_average = (d₂-d₁) / Δt
this average velocity is not necessarily the velocity of the extreme points, in the only case that it is so is when there is no acceleration.
Therefore neither of them is right.
Yes I'm pretty sure you can