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poizon [28]
3 years ago
15

A 4900 n gear box with a mass of 500kg falls to the ground. What is it’s acceleration due to gravity?

Physics
1 answer:
Lena [83]3 years ago
8 0

Answer:

9.8 m/s^2, towards the ground

Explanation:

For an object in free fall, the only force acting on it is the force of gravity. We can write it as

F=mg

where

F is called weight of the object

m is the mass of the object

g is the acceleration due to gravity

We can re-arrange the equation as

g=\frac{F}{m}

For the box in the problem, we know:

F = 4900 N

m = 500 kg

Therefore, we can find the value of g:

g=\frac{4900}{500}=9.8 m/s^2

And the direction is the same as the force of gravity (downward).

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Explanation:

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You have discovered a planet that is one-quarter the radius of Earth (Rp = 1/4R⊕) and one-half as massive (Mp = 1/2M⊕). How does
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Why does Energy appear continuous in everyday life?
lara31 [8.8K]

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3 years ago
From the top of a tall building, a gun is fired. The bullet leaves the gun at a speed of 340 m/s, parallel to the ground. As the
Ivahew [28]

Answer:

The launching point is at a distance D = 962.2m and H = 39.2m

Explanation:

It would have been easier with the drawing. This problem is a projectile launching exercise, as they give us data after the window passes and the wall collides, let's calculate with this data the speeds at the point of contact with the window.

X axis

           x = Vox t

           t = x / vox

           t = 7.1 / 340

           t = 2.09 10-2 s

In this same time the height of the window fell

           Y = Voy t - ½ g t²

Let's calculate the initial vertical speed, this speed is in the window

           Voy = (Y + ½ g t²) / t

           Voy = [0.6 + ½ 9.8 (2.09 10⁻²)²] /2.09 10⁻² = 0.579 / 0.0209

            Voy = 27.7 m / s

We already have the speed at the point of contact with the window. Now let's calculate the distance (D) and height (H) to the launch point, for this we calculate the time it takes to get from the launch point to the window; at this point the vertical speed is Vy2 = 27.7 m / s

             Vy = Voy - gt₂

             Vy = 0 -g t₂

             t₂ = Vy / g

             t₂ = 27.7 / 9.8

             t₂ = 2.83 s

This is the time it also takes to travel the horizontal and vertical distance

            X = Vox t₂

            D = 340 2.83

            D = 962.2 m

           

            Y = Voy₂– ½ g t₂²

            Y = 0 - ½ g t2

            H = Y = - ½ 9.8 2.83 2

            H = 39.2 m

The launching point is at a distance D = 962.2m and H = 39.2m

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Read 2 more answers
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