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poizon [28]
3 years ago
15

A 4900 n gear box with a mass of 500kg falls to the ground. What is it’s acceleration due to gravity?

Physics
1 answer:
Lena [83]3 years ago
8 0

Answer:

9.8 m/s^2, towards the ground

Explanation:

For an object in free fall, the only force acting on it is the force of gravity. We can write it as

F=mg

where

F is called weight of the object

m is the mass of the object

g is the acceleration due to gravity

We can re-arrange the equation as

g=\frac{F}{m}

For the box in the problem, we know:

F = 4900 N

m = 500 kg

Therefore, we can find the value of g:

g=\frac{4900}{500}=9.8 m/s^2

And the direction is the same as the force of gravity (downward).

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For the equilibrium:

\rho_{wood}gh-\rho_{oil}g(h-x)-\rho_{water}gx=0ρ

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Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to
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Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x (\frac{Rc}{Rc + Ri})

where

  • Rc = resistance of copper = \frac{ρl}{a}  (l = length , a = area, ρ = resistivity of copper)
  • Ri = resistance of iron = \frac{ρ₀l}{a}  (l = length , a = area, ρ₀ = resistivity of copper)

Vc =  V x (\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}})

Vc = V x (\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})})

Vc = V x (\frac{ρ}{ρ + ρ₀})

where

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Vc = 16 x (\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}})

Vc = 2.41 v

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3 years ago
Newton’s third law in football?
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In short, when the football is throw, there is a reaction with the ball and the player accordingly with the force put into the ball.
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