Answer:
Average net force, F = 15157.15 N
Explanation:
It is given that,
The mass of the car and riders is, ![m=3\times 10^3\ kg](https://tex.z-dn.net/?f=m%3D3%5Ctimes%2010%5E3%5C%20kg)
Initial speed of the car, u = 0
Final speed of the car, v = 43.4 m/s
Time, t = 8.59 seconds
We need to find the average net force exerted on the car and riders by the magnets. It can be calculated using second law of motion as :
F = m a
![F=m(\dfrac{v-u}{t})](https://tex.z-dn.net/?f=F%3Dm%28%5Cdfrac%7Bv-u%7D%7Bt%7D%29)
![F=3\times 10^3\ kg\times (\dfrac{43.4\ m/s-0}{8.59\ s})](https://tex.z-dn.net/?f=F%3D3%5Ctimes%2010%5E3%5C%20kg%5Ctimes%20%28%5Cdfrac%7B43.4%5C%20m%2Fs-0%7D%7B8.59%5C%20s%7D%29)
F = 15157.15 N
So, the average net force exerted on the car and riders by the magnets. Hence, this is the required solution.
Answer:
Part a)
![v = \sqrt{xg + \frac{MLg}{m}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bxg%20%2B%20%5Cfrac%7BMLg%7D%7Bm%7D%7D)
Part b)
t = 12 s
Explanation:
Part a)
Tension in the rope at a distance x from the lower end is given as
![T = \frac{m}{L}xg + Mg](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7Bm%7D%7BL%7Dxg%20%2B%20Mg)
so the speed of the wave at that position is given as
![v = \sqrt{\frac{T}{\mu}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7BT%7D%7B%5Cmu%7D%7D)
here we know that
![\mu = \frac{m}{L}](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cfrac%7Bm%7D%7BL%7D)
now we have
![v = \sqrt{\frac{ \frac{m}{L}xg + Mg}{m/L}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7B%20%5Cfrac%7Bm%7D%7BL%7Dxg%20%2B%20Mg%7D%7Bm%2FL%7D)
![v = \sqrt{xg + \frac{MLg}{m}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bxg%20%2B%20%5Cfrac%7BMLg%7D%7Bm%7D%7D)
Part b)
time taken by the wave to reach the top is given as
![t = \int \frac{dx}{\sqrt{xg + \frac{MLg}{m}}}](https://tex.z-dn.net/?f=t%20%3D%20%5Cint%20%5Cfrac%7Bdx%7D%7B%5Csqrt%7Bxg%20%2B%20%5Cfrac%7BMLg%7D%7Bm%7D%7D%7D)
![t = \frac{1}{g}(2\sqrt{xg + \frac{MLg}{m}})](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B1%7D%7Bg%7D%282%5Csqrt%7Bxg%20%2B%20%5Cfrac%7BMLg%7D%7Bm%7D%7D%29)
![t = \frac{2}{9.8}(\sqrt{(39.2\times 9.8) + \frac{8(39.2)(9.8)}{1}})](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B2%7D%7B9.8%7D%28%5Csqrt%7B%2839.2%5Ctimes%209.8%29%20%2B%20%5Cfrac%7B8%2839.2%29%289.8%29%7D%7B1%7D%7D%29)
![t = 12 s](https://tex.z-dn.net/?f=t%20%3D%2012%20s)
<h3><u>Answer;</u></h3>
= 20.436 seconds
<h3><u>Explanation;</u></h3>
Speed = Distance × time
Therefore;
Time = Distance/speed
Distance = 7.50 m, speed = 0.367 m/s
Time = 7.50/0.367
<u>= 20.436 seconds </u>
<h2>Question:</h2>
Appliances connected so that they form a single pathway for charges to flow are connected in a(n)
<h2>Answer:</h2>
<u>A</u><u>.</u><u> </u><u>Series</u><u> </u><u>circuit</u><u> </u>
<h2>
<u>#CARRYONLEARNING</u><u> </u></h2><h2>
<u>#STUDYWELL</u><u> </u></h2>
Lipids and <span>Polysaccharides r the answers hoped i helped</span>