Answer:
18.0 g H₂O
Explanation:
To find the mass of water (H₂O), you need to (1) convert grams O₂ to moles O₂ (via the molar mass), then (2) convert moles O₂ to moles H₂O (via mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂O to grams H₂O (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
2 H₂ + 1 O₂ -----> 2 H₂O
16.0 g O₂ 1 mole 2 moles H₂O 18.014 g
--------------- x ---------------- x --------------------- x ----------------- = 18.0 g H₂O
31.996 g 1 mole O₂ 1 mole
Answer:
C) 2 H₂ + O₂ → 2 H₂O
Explanation:
4 atoms of hydrogen on reactant side
2 atoms of oxygen on reactant side
4 atoms of hydrogen on product side
2 atoms of oxygen on product side
Answer:
C. 33.6L
Explanation:
Based on the reaction, 2 moles of HCl reacts producing 1 mole of hydrogen.
To solve this question we must find the moles of hydrogen produced using the reaction. Then, with combined gas law (PV = nRT) we can find the volume produced:
<em>Moles H2:</em>
3.00 moles HCl * (1mol H2 / 2mol HCl) = 1.50 moles H2 are produced
<em>Volume:</em>
PV = nRT
V = nRT / P
<em>Where P is pressure = 1atm at STP</em>
<em>V is volume = Our incognite</em>
<em>n are moles of the gas = 1.50 moles</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 273.15K</em>
<em />
V = nRT / P
V = 1.50mol*0.082atmL/molK*273.15K / 1atm
V = 33.6L
<h3>C. 33.6L</h3>
