What is the variable that a scientist changes when conducting an experiment

The fraction of Earth's radius (6371 km) relative to the thickness of the oceanic (7.5 km) and continental crust (35 km) is 0.12 and 0.55, respectively.

What we know:

The average radius of Earth (E) = 6371 km

The average thickness of oceanic crust (O) = 7.5 km

The average thickness of continental crust (C) = 35 km

We need to convert all the above units from kilometers to miles:

$E = \frac{0.6214 mi}{1 km}*6371 km = 3958.9 mi$

$O = \frac{0.6214 mi}{1 km}*7.5 km = 4.7 mi$

$C = \frac{0.6214 mi}{1 km}*35 km = 21.7 mi$

Now, we can calculate the fraction of Earth's radius relative to each type of crust, with the given equation:

$X = \frac{avg. \: thickness}{avg. \: radius} \times 100$

For the oceanic crust (O):

$X = \frac{4.7 mi}{3958.9 mi}\times 100 = 0.12$

For the continental crust (C):

$X = \frac{21.7 mi}{3958.9 mi}\times 100 = 0.55$

Therefore, the fraction of Earth's radius relative to the oceanic and continental crust is 0.12 and 0.55, respectively.

You can see another example of calculation of fractions of Earth's radius here: brainly.com/question/4675868?referrer=searchResults

I hope it helps you!

6 0

2 years ago

What happens when two hydrogen atoms enter the ETS as part of either NADH or FADH2? Two hydrogen and one oxygen react to form a

gtnhenbr [62]

I think the correct answer from the choices listed above is the second option. When two hydrogen atoms enter the ETS as part of either NADH or FADH2, the two hydrogen atoms are split into two H+ and two electrons. Hope this answers the questions.

7 0

2 years ago

Read 2 more answers

What is the concentration of hydrogen ions in a solution of KOH with a pOH of 1.72?

bezimeni [28]

Answer:

[h+]= 5.25e-13

Explanation:

pH= 14-1.72= 12.28

[h+]= 5.25e-13

3 0

3 years ago