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Mamont248 [21]
4 years ago
6

At most, how many bright fringes can be formed on one side of the central bright fringe (not counting the central bright fringe)

when light of 625 nm falls on a double slit whose spacing is 6.77 x 10-6 m?
Chemistry
1 answer:
lilavasa [31]4 years ago
4 0
Where are the answer choies ?
You might be interested in
how would physical changes to Earth such as an iceberg or rising sea levels lead to physical changes in organisms?
vlabodo [156]
If there was more water area and less land more animals would adapt to the water life than land. Like for example more evolving fins or even amphibians
just staying in water and no longer needing legs or the things they use for living on the land. 

7 0
3 years ago
How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?
Semenov [28]
Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!
3 0
3 years ago
Read 2 more answers
Convert 121cm to mm
Ray Of Light [21]

Answer:

1210

Explanation:

Because the 121 cm times 10 is 1210

4 0
3 years ago
Which group would Ns2np2 go into
FrozenT [24]

Answer:

The group 15 elements: the pnicogens

Explanation:

The group 15 elements, nitrogen, phosphorus, arsenic, antimony and bismuth, all have the general valence shell electronic configuration ns2np3. They can all exist in the +3 or +5 oxidation state, with the +3 state increasing in stability as we move vertically down the group.

3 0
3 years ago
Read 2 more answers
What is the molality of a solution that contains 1.34 moles of NaCl in 2.47 kg of solvent
dsp73

The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

<u>Explanation:</u>

Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.

         \text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}

As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.

Hence, \text { molality }=\frac{1.34}{2.47}= 0.54 \mathrm{M}

Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

8 0
3 years ago
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