Answer:
290 grams
Explanation:
Let's begin by writing the balanced chemical equations:

Then we calculate the number of moles in 97g of propane.
n(propane)=
According to the balanced chemical equation, one mole of propane produces 3 moles of carbon dioxide. So the available number of moles of propane must be multiplied by three to work out the number of carbon dioxide produced.
n(carbon dioxide)= 2.1995mol*3 = 6.5985mol
mass(carbon dioxide) = moles * molar mass
= 6.5985 mol * 44.01 g/mol
= 290 grams
Climate change or it could just be Climate,
Hopefully that helps ❤
The different types of motion

B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
Hey Brayden!
Rain showers had continued over a particular area for several days. Which of these weather factors is most likely responsible?
Answer - A Stationary front
Hope This Helps!
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