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Doss [256]
2 years ago
15

How many discovered planets are there

Physics
1 answer:
Allisa [31]2 years ago
5 0
We have discovered 786 planets. Most of which were only recently discovered.
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Explain what is meant by “field” and compare the properties of gravitational, electric, and magnetic forces in terms of particle
Tema [17]
A field is the description of a spatial region, the force exerted on objects by a field is a field force. 
gravitational force field: surrounds every material object, although only objects planet-sized or larger exert significant gravity.
electric force field: surrounds and affect electrical charges
magnetic force field: surround magnets and materials with electricity flowing through them. magnetic fields affect susceptible materials such as iron or other magnets.
hope i helped a little

6 0
2 years ago
Read 2 more answers
A. In your own words, define what a longitudinal wave is.
Stella [2.4K]

Answer:

Longitudinal wave is a type of wave in which the the movement of the wave particle is parallel to the direction of the wave propagation. This simply means that the wave particles is in the same or opposite direction to the wave propagation.

B. Sound waves- These are longitudinal waves because its medium particles through which the sound is transported oscillates parallel to the direction of the movement of the sound wave.

7 0
3 years ago
Things that are _______________________ cannot be broken down by living organisms.
Pavlova-9 [17]

Answer:

I would say the answer is Non-Biodegradable......eg, plastics, rubber, metals,etc.

HOPE THIS HELPS.

8 0
3 years ago
A sound wave of frequency
Artyom0805 [142]

Answer:

0.283m

Explanation:

Speed (v) = wavelength × Frequency (f)

Wavelength = speed/ frequency

Wavelength = 343/ 1210 = 0.283m

8 0
3 years ago
A velocity selector, in which charged particles of a specific speed pass through undeflected while those of greater or lesser sp
uranmaximum [27]

Answer:

a) 351351.35m/s

b) 1.044*10^{-8}kg/C

Explanation:

a) Electric force and magnetic force over the charge must have the same magnitude. From there we can compute the seep of the charge.

F_E=F_B\\\\qE=qvB\\\\v=\frac{E}{B}=\frac{1.95*10^{5}V/m}{0.555T}=351351.35\frac{m}{s}

b) the mass-charge ratio is given by:

\frac{m}{q}=\frac{rB}{v}=\frac{(6.61*10^{-3}m)(0.555T)}{351351.35m/s}=1.044*10^{-8}\frac{kg}{C}

hope this helps!!

5 0
3 years ago
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