I believe it’s 60km/h
I divided the total distance (120 km) by the time it took to get there (2h) to get this.
Answer:
a).11.546J
b).2.957kW
Explanation:
Using Inertia and tangential velocity
a).


Now using Inertia an w

average power=
b).
power=t*w
P=
P=2.957 kW
Answer:
answer is 2 option because more force is applied