The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
where
is the charge density
is the vacuum permittivity
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
Mass and velocity are the two terms which affect momentum of a bicycle going hill down.
Explanation:
As we know that Momentum describes the motion of an object. It is the combination of the objects mass and velocity.
So, obviously with no doubt mass and velocity are the two terms which affect momentum.
Momentum(p) = Mass(m) * Velocity(v)
The momentum also depends upon the mass and speed of the object.
More the mass of the object more is the momentum.
Depending upon the gravity and bicycle's motion speed momentum varies.
Bicycle moves faster the down hill if it moves with some speed as it has lesser mass the momentum also will be less.
The statements that are held true with regards to the static equilibrium of bodies are:
<span>The net torque acting on the object must equal zero
</span><span>The net torque on the object does not have to be zero if the net force on the object is zero
Furthermore, when a body is in a state of static equilibrium, the summation of all forces, either vertically or horizontally, must be equal to zero. </span>
Hey, Name's Jessy. I hope, I answer your question.
Nearly 400 lbs,by 11.73%.
Answer:
6.003×10¯⁶ N
Explanation:
We'll begin by converting 1 cm to m. This can be obtained as follow:
100 cm = 1 m
Therefore,
1 cm = 1 cm × 1 m / 100 cm
1 cm = 0.01 m
Finally, we shall determine the gravitational attraction. This can be obtained as follow:
Mass 1 (M₁) = 3 Kg
Mass 2 (M₂) = 3 Kg
Distance apart (r) = 0.01 m
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Force of attraction (F) =?
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × 3 × / 0.01²
F = 6.003×10¯¹⁰ / 1×10¯⁴
F = 6.003×10¯⁶ N
Thus the gravitational attraction is 6.003×10¯⁶ N
