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BabaBlast [244]
3 years ago
12

Brainly if u awnser!

Mathematics
1 answer:
just olya [345]3 years ago
4 0

The formula of a perimeter of a rectangle l × w:

P = 2l + 2w

We have the perimeter P = 76 cm and the length l = 20 cm. Substitute:

76 = 2(20) + 2w

76 = 40 + 2w    <em>subtract 40 from both sides</em>

36 = 2w     <em>divide both sides by 2</em>

18 = w

Answer: width = 18 cm.

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Can anyone help me with this question ?
TEA [102]

Answer:

addition

Step-by-step explanation:

18 (<u> d </u> - 9 ) = 198

     3

divide both side by 18

<u> d </u> - 9 = <u> 198 </u>  

3             18

<u> d </u> - 9 = 11

3

multiply both sides by 3

d - 27 = 33

add 27 to both sides

d = 33 + 27

lastly, add them together

d = 60

therefore, the last step is addition

8 0
3 years ago
If f(x)=12x+2(x-1), find f(6)
zavuch27 [327]

Answer:

12x6+2(6-1)

72+2x5

72+10

82

82 is the answer.

Step-by-step explanation:

Just replace the X's in the problem with 6.

5 0
4 years ago
Rita, Tony, and Deon have a total of $86 in their wallets. Rita has $ 10 less than Tony. Deon has 2 times what Rita has. How muc
8090 [49]
29-10 = 19
19(2) = 38
38+19+29=86
8 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
25x^2+40x+16=28<br><br><br><br><br>Ansa ASAP
Paha777 [63]
Solution:
1. Move all terms to one side
<span>25{x}^{2}+40x+16-28=0</span>  2. Simplify <span>25{x}^{2}+40x+16-28 to <span>25<span>x<span><span>​2</span><span>​​</span></span></span>+40x</span></span><span><span>−12</span></span>
<span>25{x}^{2}+40x-12=0</span>  3. Apply the Quadratic Formula<span>x=\frac{-40+20\sqrt{7}}{50},\frac{-40-20\sqrt{7}}{50}

</span> 4. Simplify solutions
<span>x=-\frac{2(2-\sqrt{7})}{5},-\frac{2(2+\sqrt{7})}{5}</span> Done!
8 0
3 years ago
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