Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
(B) -25/4
Step-by-step explanation:
-5/3 ÷ 4/15
Copy dot flip
-5/3 * 15/4
Rewriting for easier math
-5/4 * 15/3
-5/4 * 5
-25/4
Answer:
Step-by-step explanation:
length =15 feet
width =10 feet
Answer:
B) 12
Step-by-step explanation:
C is the circumference, d is the diameter, and r is the radius. They are related by the following equations:
d = 2r
C = πd = 2πr
If d = 6.0, then r = 3.0.
If C / C' = 0.25, then:
(2πr) / (2πr') = 0.25
r / r' = 0.25
3 / r' = 0.25
r' = 12
