Answer:
what is these problems for? like what lesson in your book?
Step-by-step explanation:
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The radius of the base of a cone is 4 inches. The slant height of the cone is 6 inches. Which is closest to the surface area of the cone ?
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
Radius (r) of the base of a cone is 4 inches.
Slant height (l) of the cone is 6 inches.
<h3>To Find:-</h3>
Which is closest to the surface area of the cone ?
<h2>Solution:-</h2>
We know,
Formula of surface area of a cone is πr(r + l) sq. units.
Taking value of π = 3.14
So, Surface area of the cone = 3.14 × 4(4 + 6)
Surface area of the cone = 12.56 × 10
Surface area of the cone = 125.6 sq. inches.
126 sq. inches is closest to 125.6 sq. inches.
So, option (H) <u>1</u><u>2</u><u>6</u><u> </u><u>s</u><u>q</u><u>.</u><u> </u><u>i</u><u>n</u> is correct. [Answer]
Because, if 6 + 6 = 12, then in 6 + 7, 7 can be splitted into 6 + 6 + 1, and so you find it easier...!!
<span>2 square root (x - 5) = 2. 2^2 (x -5) = 2^2. 4(x - 5) = 4. 4x - 20 = 4. 4x = 24. x = 6. This solution is not extraneous, because extraneous solutions emerge from solving the problem but are not actually valid solutions for the initial problem. With rounding, this solution is valid for the initial problem.</span>
42-6=? (Answer) 36
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