The mass of ethanol is consumed by the reaction of 3.37g oxygen gas is 4.85g
Explanation:
The balanced equation for the chemical reactions is;
CH₃CH₂OH + O₂ → CH₃COOH + H₂O
The mole ratio between oxygen and ethanol in the reaction is 1 : 1
The molar mass of O₂ is 32g / mole. Therefore the O₂ moles consumes in the reaction is;
3.37 / 32
If the molar mass of ethanol is 46.07g/mole, and the ration of reaction in 1 : 1; Then the moles of ethanol consumed is;
3.37/32 * 46.07
= 4.85g
The planets speed as they orbit the sun
Answer:

Explanation:
<h3>Electronic configuration:</h3>

The outermost/valence shell is the second one, seeing from the electronic configuration.
<h3>Valence electrons:</h3>
= 2 + 1 = 3 (electrons are raised to the power in the electronic configuration)
Since, the valence shell here is 2, the electrons of second shell will be counted as valence electrons.
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<u>Answer:</u> No crystals of potassium sulfate will be seen at 0°C for the given amount.
<u>Explanation:</u>
We are given:
Mass of potassium nitrate = 47.6 g
Mass of potassium sulfate = 8.4 g
Mass of water = 130. g
Solubility of potassium sulfate in water at 0°C = 7.4 g/100 g
This means that 7.4 grams of potassium sulfate is soluble in 100 grams of water
Applying unitary method:
In 100 grams of water, the amount of potassium sulfate dissolved is 7.4 grams
So, in 130 grams of water, the amount of potassium sulfate dissolved will be 
As, the soluble amount is greater than the given amount of potassium sulfate
This means that, all of potassium sulfate will be dissolved.
Hence, no crystals of potassium sulfate will be seen at 0°C for the given amount.
A I have a periodic table with me I checked