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V125BC [204]
3 years ago
7

Silicon has three naturally occurring isotopes. Silicon-28 has a mass of 27.98 and a relative abundance of 92.23%. Silicon-29 ha

s a mass of 28.98 and a relative abundance of 4.68%. Silicon-30 has a mass of 29.97 and a relative abundance of 3.09%. What is the weighted average atomic mass of silicon?
Chemistry
2 answers:
Advocard [28]3 years ago
5 0
The weighted average atomic mass of Silicon is 28.1

(27.98 x .9223) + (28.98 x .0468) + (29.97 x .0309) 
= 25.81 + 1.36 + .93
= 28.1
skad [1K]3 years ago
4 0

Answer : The atomic mass of the silicon is, 28.09 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Mass of isotope, Silicon-28 = 27.98 amu

Percentage abundance of isotope, Silicon-28 = 92.23 %

Fractional abundance of isotope, Silicon-28 = 0.9223

Mass of isotope, Silicon-29 = 28.98 amu

Percentage abundance of isotope, Silicon-29 = 4.68 %

Fractional abundance of isotope, Silicon-29 = 0.0468

Mass of isotope, Silicon-30 = 29.97 amu

Percentage abundance of isotope, Silicon-30 = 3.09 %

Fractional abundance of isotope, Silicon-30 = 0.0309

Now put all the given values in above formula, we get:

\text{Average atomic mass of element}=\sum[(27.98\times 0.9223)+(28.98\times 0.0468)+(29.97\times 0.0309)]

\text{Average atomic mass of element}=28.09amu

Therefore, the atomic mass of the silicon is, 28.09 amu

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he total number of each of the atoms on the left and the right are the same thus the reaction equation is balanced.

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4 0
1 year ago
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Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

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ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)  ...........................(*)

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In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca)  = 0 KJ

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Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

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ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

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8 0
3 years ago
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