Slow it down - I believe?
Ions and charges= Al+3 SO3-2
The charges must add up to zero, in order for two +3 aluminum ions to cancel out three -2 sulfite ions.
Al+3 Al+3 SO3-2 SO3-2 SO3-2
<span>So simply put : </span>Al2(SO3)<span>3 </span>
Each Ba(OH)2 requires 2 Cl to produce one BaCl2 molecule.
<span>The 2 H's from the 2 HCl molecules combine with the 2 (OH) to form 2 H2O molecules. </span>
<span>2 HCl (aq) + Ba(OH)2 (s) ==> BaCl2 (aq) + 2 H2O (l)
I hope the answer will help you. </span>
It gives you the amount of shells, electrons, the type of group it’s one for example: metalloids. The protons and neutrons in that group.
