A horizontal pipe has varying cross-section, with one section having a diameter of 5.5

A sample of the material halite measures 3.18 cm long by 3.06 cm wide by 2.79 cm high and has a mass of 58.75 g. What is the its

tatiyna

Specific gravity = Density of an object/Density of water

Density = Mass/Volume

For the current scenario;

Density of halite = mass/(l*w*h) = 58.75/(3.18*3.06*2.79) = 58.75/27.148932 = 2.164 g/cm^3

Density of water ≈ 1000 kg/m^3 = 1 g/cm^3

Therefore,
Specific density of halite = 2.164 g/cm^3 / 1 g/cm^3 = 2.164

3 0

3 years ago

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Which best describes the main difference between science and pseudoscience

Mice21 [21]

Science
DefineA body of knowledge and the process of gaining new knowledgePseudoscience
DefineSometimes a practice or a belief claims to be science, but does not follow specific criteria. Criteria that define true science include scientific experimentation, replication of results,and peer review. Beliefs and claims that do not meet these criteria are called pseudoscience

6 0

3 years ago

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Im so confused can someone help. I’ll give you BRAINLIETS

Hatshy [7]

I found the answer sheet online for you

3 0

2 years ago

A box falls off of a tailgate and slides along the street for a distance of 62.5 m. Friction slows the box at –5.0 m/s2. At what

Mila [183]

Answer:

25 m/s

Explanation:

This question can be solved using equation of motion

$v^2 = u^2 + 2as$

where

v is the final velocity

u is the initial velocity

s is the distance covered while moving from initial to final velocity

a is the acceleration

_____________________________________________

Given

box moved for distance of 62.5 m

Friction slows the box at –5.0 m/s2----> this statement means that there is deceleration , speed of truck decreases by 5 m/s in every second until the box comes to rest. Friction causes this deceleration.

thus in this problem

a = -5.0 m/s2

V = 0 as body came to rest due to friction deceleration

u the initial velocity we have to find

the initial velocity of box will be the same as speed of truck, as the box was in the truck and hence box will pick the speed of truck.

so if we find speed of box, we will be able get sped of truck as well.

using equation of motion

$v^2 = u^2 + 2as\\0^2 = u^2 + 2*-5* 62.5\\0 = u^2 - 625\\u^2 = 625\\\sqrt{u^2} = \sqrt{625} \\u = 25$

Thus, initial speed with the truck was travelling was 25 m/s.

3 0

2 years ago

A horizontal force of 12N is applied to 1.5kg of block which rests on a horizontal surface. If the coefficient friction is 0.3,

Rama09 [41]

Answer:

7 m/s²

Explanation:

From the question given above, the following data were:

Force applied (Fₐ) = 15 N

Mass (m) of block = 1.5 Kg

Acceleration due to gravity (g) = 10 m/s²

Coefficient of friction (μ) = 0.3

Acceleration (a) of block =?

Next, we shall determine the frictional force. This can be obtained as follow:

Mass (m) of block = 1.5 Kg

Acceleration due to gravity (g) = 10 m/s²

Coefficient of friction (μ) = 0.3

Normal reaction (R) = mg = 1.5 × 10 = 15 N

Frictional force (Fբ) =?

Fբ = μR

Fբ = 0.3 × 15

Fբ = 4.5 N

Next, we shall determine the net force acting on the block. This can be obtained as follow:

Force applied (Fₐ) = 15 N

Frictional force (Fբ) = 4.5 N

Net force (Fₙ) =.?

Fₙ = Fₐ – Fբ

Fₙ = 15 – 4.5

Fₙ = 10.5 N

Finally, we shall determine the acceleration produced in the block. This can be obtained as follow:

Mass (m) of block = 1.5 Kg

Net force (Fₙ) = 10.5 N

Acceleration (a) of block =?

Fₙ = ma

10.5 = 1.5 × a

Divide both side by a

a = 10.5 / 1.5

a = 7 m/s²

Therefore, the acceleration produced in the block is 7 m/s²

8 0

3 years ago